Jaweria
Help me Please. e^x-1-5=5.
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Jaweria
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Helpl please
yakeyglee
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Solve for \(e^{x-1}\) and take the natural logarithm of both sides.
Jaweria
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I started this problem but its giving me a wrong answer
can u please explain this to me?
yakeyglee
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Well, tell me, what do you get when you solve for \(e^{x-1}\)?
Jaweria
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can anyone help me here please?
stamp
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\[e^x-1-5=5.\]\[e^x-6=5\]\[e^x=11\]\[ln(e^x)=ln(11)\]\[xln(e)=ln(11)\]\[x=ln(11)\]
Jaweria
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Sorry but the answer is wrong
answer suppose to be 3.3026
stamp
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@Jaweria Then you wrote it down wrong.
Jaweria
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ok let me fix it
Jaweria
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\[e ^{x-1}-5=5\]
stamp
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\[e^{x-1}-5=5\]Isolate e term.\[e^{x-1}=10\]Natural log of both sides.\[lne^{x-1}=ln(10)\]Properties of logatrithms.\[(x-1)lne=ln(10)\]lne = 1.\[x-1=ln(10)\]Solve for x.\[x=ln(10)+1\]
Jaweria
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Sorry but I have one more question if you dont mind ?
Jaweria
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\[9^{n+10}+3=81\]
stamp
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\[9^{n+10}+3=81\]\[9^{n+10}=81-3\]\[ln9^{n+10}=ln78\]\[n+10=ln78/ln9\]\[n=ln78/ln9-10\]
Jaweria
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Thanks :)
Jaweria
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Thanks for this :)
Jaweria
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I m having trouble with this question. \[-2 \log_{5}7x=2 \]
stamp
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\[-2log_57x=2\]\[log_57x=-1\]\[log_ax=y\]\[a^y=x\]\[5^{-1}=7x\]\[\frac{1}{5}=7x\]\[x=1/35\]
Jaweria
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Thanks
Jaweria
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I m working on this problem so far I got this but my answer is not matching with my professor's. |dw:1361342182376:dw|
Jaweria
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Can anyone please help me ??
whpalmer4
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Is that \[5*6^{3m} = 20\]?
Jaweria
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yes
whpalmer4
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I'll assume it is, if it isn't, maybe the example will help you.
\[5*6^{3m} = 20\]Divide both sides by 5\[6^{3m}=4\]Take natural log of both sides\[3m \ln 6 = \ln 4\]Divide both sides by \( 3 \ln 6\)\[m = \frac{\ln 4}{3 \ln 6}\]
Jaweria
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thanks