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Jaweria

  • 2 years ago

Help me Please. e^x-1-5=5.

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  1. Jaweria
    • 2 years ago
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    Helpl please

  2. yakeyglee
    • 2 years ago
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    Solve for \(e^{x-1}\) and take the natural logarithm of both sides.

  3. Jaweria
    • 2 years ago
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    I started this problem but its giving me a wrong answer can u please explain this to me?

  4. yakeyglee
    • 2 years ago
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    Well, tell me, what do you get when you solve for \(e^{x-1}\)?

  5. Jaweria
    • 2 years ago
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    can anyone help me here please?

  6. stamp
    • 2 years ago
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    \[e^x-1-5=5.\]\[e^x-6=5\]\[e^x=11\]\[ln(e^x)=ln(11)\]\[xln(e)=ln(11)\]\[x=ln(11)\]

  7. Jaweria
    • 2 years ago
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    Sorry but the answer is wrong answer suppose to be 3.3026

  8. stamp
    • 2 years ago
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    @Jaweria Then you wrote it down wrong.

  9. Jaweria
    • 2 years ago
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    ok let me fix it

  10. Jaweria
    • 2 years ago
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    \[e ^{x-1}-5=5\]

  11. stamp
    • 2 years ago
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    \[e^{x-1}-5=5\]Isolate e term.\[e^{x-1}=10\]Natural log of both sides.\[lne^{x-1}=ln(10)\]Properties of logatrithms.\[(x-1)lne=ln(10)\]lne = 1.\[x-1=ln(10)\]Solve for x.\[x=ln(10)+1\]

  12. Jaweria
    • 2 years ago
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    Sorry but I have one more question if you dont mind ?

  13. Jaweria
    • 2 years ago
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    \[9^{n+10}+3=81\]

  14. stamp
    • 2 years ago
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    \[9^{n+10}+3=81\]\[9^{n+10}=81-3\]\[ln9^{n+10}=ln78\]\[n+10=ln78/ln9\]\[n=ln78/ln9-10\]

  15. Jaweria
    • 2 years ago
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    Thanks :)

  16. stamp
    • 2 years ago
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    @Jaweria Properties of Logarithms http://www.andrews.edu/~calkins/math/webtexts/numb17.htm

  17. Jaweria
    • 2 years ago
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    Thanks for this :)

  18. Jaweria
    • 2 years ago
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    I m having trouble with this question. \[-2 \log_{5}7x=2 \]

  19. stamp
    • 2 years ago
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    \[-2log_57x=2\]\[log_57x=-1\]\[log_ax=y\]\[a^y=x\]\[5^{-1}=7x\]\[\frac{1}{5}=7x\]\[x=1/35\]

  20. Jaweria
    • 2 years ago
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    Thanks

  21. Jaweria
    • 2 years ago
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    I m working on this problem so far I got this but my answer is not matching with my professor's. |dw:1361342182376:dw|

  22. Jaweria
    • 2 years ago
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    Can anyone please help me ??

  23. whpalmer4
    • 2 years ago
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    Is that \[5*6^{3m} = 20\]?

  24. Jaweria
    • 2 years ago
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    yes

  25. whpalmer4
    • 2 years ago
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    I'll assume it is, if it isn't, maybe the example will help you. \[5*6^{3m} = 20\]Divide both sides by 5\[6^{3m}=4\]Take natural log of both sides\[3m \ln 6 = \ln 4\]Divide both sides by \( 3 \ln 6\)\[m = \frac{\ln 4}{3 \ln 6}\]

  26. Jaweria
    • 2 years ago
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    thanks

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