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Garcia_123

  • one year ago

Determine whether the given procedure results in a binomial distribution. If not, state the reason why. Rolling a single die 57 times, keeping track of the numbers that are rolled.

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  1. jim_thompson5910
    • one year ago
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    Hint: a binomial distribution is the result of doing n Bernoulli trials (and each trial is independent with the same probability of success) a Bernoulli trial is a trial with exactly two outcomes

  2. jim_thompson5910
    • one year ago
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    a good example is flipping a coin you either get heads or tails

  3. kropot72
    • one year ago
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    On the condition that rolling a particular number was regarded as a success and rolling any other number was a failure, the procedure will result in a binomial distribution.

  4. kropot72
    • one year ago
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    @jim_thompson5910 Have you any comment?

  5. jim_thompson5910
    • one year ago
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    yes if you said something like "rolling an even number" then it would be a binomial distribution since there are only two options: rolling an even or rolling an odd but it doesn't give such restrictions

  6. jim_thompson5910
    • one year ago
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    it just says "keeping track of the numbers that are rolled" so you would have some probability distribution, but it wouldn't be a binomial distribution

  7. Garcia_123
    • one year ago
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    ok, then its not binomial

  8. jim_thompson5910
    • one year ago
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    yeah you have 6 possible outcomes per trial, not 2

  9. kropot72
    • one year ago
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    The binomial distribution can be used to give the probability of the number of 1s, 2s, 3s etc when the die is rolled 57 times.

  10. Garcia_123
    • one year ago
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    2 outcomes for a trial

  11. Garcia_123
    • one year ago
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    * yeah more than 2

  12. jim_thompson5910
    • one year ago
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    true you could use it like that, but it doesn't specify which number you're going for so I'm assuming they're just saying in general that you have 6 outcomes instead of 2

  13. Garcia_123
    • one year ago
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    okie ! thank you @kropot72 and @jim_thompson5910 (y) ;) great help

  14. kropot72
    • one year ago
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    It depends on how the trial is defined. I agree that the expected answer to the question is that the procedure in itself does not meet the requirements for a binomial distribution.

  15. Garcia_123
    • one year ago
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    ;)

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