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emerald64
Group Title
What is the implicit differentiation of xsiny+cos2y=cosy
 one year ago
 one year ago
emerald64 Group Title
What is the implicit differentiation of xsiny+cos2y=cosy
 one year ago
 one year ago

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Novice_1 Group TitleBest ResponseYou've already chosen the best response.1
Try and solve it yourselves, taking help from the step below. 1. differentiate the whole equation with respect to x, taking y as constant. name it 'U' 2. repeat step one but this time differentiate with respect to y taking x as constant. name it as 'V' 3. Dy/Dx =  (U/V)
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
You need to know a few rules: (y)'=y' (x)'=1 (fg)'=f'g+fg' (cos(x))'=sin(x) (sin(x))'=cos(x) (f(g(x)))'=g'(x) * f '(g(x))
 one year ago

emerald64 Group TitleBest ResponseYou've already chosen the best response.0
i tried it and i got siny + xcos(y) dx/dy  sin (2y) * 2 dy/dx but im so confused on what to do next
 one year ago

Novice_1 Group TitleBest ResponseYou've already chosen the best response.1
Follow my steps.. Assume Y is a constant.. then differentiate for x.. then assume X as constant.. read my reply dude..!
 one year ago

emerald64 Group TitleBest ResponseYou've already chosen the best response.0
ah i got it. thanks!
 one year ago
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