## A community for students. Sign up today

Here's the question you clicked on:

## raimelgarcia5 2 years ago The number of customers visiting a local business is 48,961 and has been continuously declining at a rate of 2.5% each year. What is the approximate number of customers in 13 years?

• This Question is Closed
1. raimelgarcia5

pleaseee help!.... im doing an exam now... i dont get this one :/

2. raimelgarcia5

@Luis_Rivera @KonradZuse

3. KonradZuse

No cheating n exams... sorry...

4. raimelgarcia5

I'm not cheating.. its not an exam... its a practice for exam.. and I dont get hwo to do that... come on.. please a lil help would be appreciated... like, explain.. dont do it... please

5. raimelgarcia5

I dont know which formula to use... if the compound interest function, or the continuous change function

6. KonradZuse

You have some # 48k. you want 2.5% continously....

7. raimelgarcia5

well: A = 48961e^(0.975*13) ?? is that right? (I dont know if the percent is?

8. raimelgarcia5

then: A= 48961e^12.675 A= 48961*319655.78 A= 15650666514.54 (U see, this is soooo not right!) :/

9. KonradZuse

where doyou get .975?

10. raimelgarcia5

(1-0.025) because is depreciating right? and its 2.5%

11. KonradZuse

I have no idea honestly....

12. raimelgarcia5

:_( thanks though! @AriPotta @Agent_Sniffles @abb0t @andriod09 @Alyx_da_Boss @bloodrain

13. raimelgarcia5

@Dunce

14. KonradZuse

stop

15. KonradZuse

@dpaInc any idea on this one? @TuringTest

16. raimelgarcia5

thanks

17. Dunce

I can think of a long way to do it. 48961- (0.025*48961)=A(customer base after 1 year) A-(0.025*A)=B(customer base after 2 years) B-(0.025*B)=C(3 years.....) and so on. There is probably an easier way to solve this with n! or something, but I don't know off hand.

18. dpaInc

^^ that's basically the way to do it Since it's continuously declining, you can also use: \(\large y=Ce^{kt} \) where C is your initial number of customers and k = -0.025. Plug in t=13 and you should get 35375.66

#### Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy