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The number of customers visiting a local business is 48,961 and has been continuously declining at a rate of 2.5% each year. What is the approximate number of customers in 13 years?
 one year ago
 one year ago
The number of customers visiting a local business is 48,961 and has been continuously declining at a rate of 2.5% each year. What is the approximate number of customers in 13 years?
 one year ago
 one year ago

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raimelgarcia5Best ResponseYou've already chosen the best response.0
pleaseee help!.... im doing an exam now... i dont get this one :/
 one year ago

raimelgarcia5Best ResponseYou've already chosen the best response.0
@Luis_Rivera @KonradZuse
 one year ago

KonradZuseBest ResponseYou've already chosen the best response.0
No cheating n exams... sorry...
 one year ago

raimelgarcia5Best ResponseYou've already chosen the best response.0
I'm not cheating.. its not an exam... its a practice for exam.. and I dont get hwo to do that... come on.. please a lil help would be appreciated... like, explain.. dont do it... please
 one year ago

raimelgarcia5Best ResponseYou've already chosen the best response.0
I dont know which formula to use... if the compound interest function, or the continuous change function
 one year ago

KonradZuseBest ResponseYou've already chosen the best response.0
You have some # 48k. you want 2.5% continously....
 one year ago

raimelgarcia5Best ResponseYou've already chosen the best response.0
well: A = 48961e^(0.975*13) ?? is that right? (I dont know if the percent is?
 one year ago

raimelgarcia5Best ResponseYou've already chosen the best response.0
then: A= 48961e^12.675 A= 48961*319655.78 A= 15650666514.54 (U see, this is soooo not right!) :/
 one year ago

KonradZuseBest ResponseYou've already chosen the best response.0
where doyou get .975?
 one year ago

raimelgarcia5Best ResponseYou've already chosen the best response.0
(10.025) because is depreciating right? and its 2.5%
 one year ago

KonradZuseBest ResponseYou've already chosen the best response.0
I have no idea honestly....
 one year ago

raimelgarcia5Best ResponseYou've already chosen the best response.0
:_( thanks though! @AriPotta @Agent_Sniffles @abb0t @andriod09 @Alyx_da_Boss @bloodrain
 one year ago

KonradZuseBest ResponseYou've already chosen the best response.0
@dpaInc any idea on this one? @TuringTest
 one year ago

DunceBest ResponseYou've already chosen the best response.0
I can think of a long way to do it. 48961 (0.025*48961)=A(customer base after 1 year) A(0.025*A)=B(customer base after 2 years) B(0.025*B)=C(3 years.....) and so on. There is probably an easier way to solve this with n! or something, but I don't know off hand.
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
^^ that's basically the way to do it Since it's continuously declining, you can also use: \(\large y=Ce^{kt} \) where C is your initial number of customers and k = 0.025. Plug in t=13 and you should get 35375.66
 one year ago
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