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|dw:1361407430942:dw|
how this gets to \[\ln \sqrt{2}\]

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Other answers:

ln(1) = 0
i know that so |dw:1361408007302:dw|
You MUST have been given fundamental principles of logarithms, Here's one: log(a) + log(b) = log(a*b) Have you any others?
i dont get this
this is - so division right
Good. log(a) - log(b) = log(a/b) Any more?
|dw:1361408413459:dw|
so ln(2)/(2)
how did they got ln sqrt 2
So, you're saying you have only two properties for logarithms? You don't have this one: \(a\cdot \log(b) = \log\left(b^{a}\right)\)?
|dw:1361408835272:dw| where do u use that
\(\dfrac{\ln(2)}{2} = \dfrac{1}{2}\cdot \ln(2) = ln\left(2^{1/2}\right) = \ln(\sqrt{2})\) It's all in the properties!
wow thx

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