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ksaimouli
 3 years ago
slove
ksaimouli
 3 years ago
slove

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ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1361407430942:dw

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0how this gets to \[\ln \sqrt{2}\]

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0i know that so dw:1361408007302:dw

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1You MUST have been given fundamental principles of logarithms, Here's one: log(a) + log(b) = log(a*b) Have you any others?

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0this is  so division right

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1Good. log(a)  log(b) = log(a/b) Any more?

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1361408413459:dw

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0how did they got ln sqrt 2

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1So, you're saying you have only two properties for logarithms? You don't have this one: \(a\cdot \log(b) = \log\left(b^{a}\right)\)?

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1361408835272:dw where do u use that

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1\(\dfrac{\ln(2)}{2} = \dfrac{1}{2}\cdot \ln(2) = ln\left(2^{1/2}\right) = \ln(\sqrt{2})\) It's all in the properties!
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