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ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.0dw:1361407430942:dw

ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.0how this gets to \[\ln \sqrt{2}\]

ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.0i know that so dw:1361408007302:dw

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.1You MUST have been given fundamental principles of logarithms, Here's one: log(a) + log(b) = log(a*b) Have you any others?

ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.0this is  so division right

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.1Good. log(a)  log(b) = log(a/b) Any more?

ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.0dw:1361408413459:dw

ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.0how did they got ln sqrt 2

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.1So, you're saying you have only two properties for logarithms? You don't have this one: \(a\cdot \log(b) = \log\left(b^{a}\right)\)?

ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.0dw:1361408835272:dw where do u use that

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.1\(\dfrac{\ln(2)}{2} = \dfrac{1}{2}\cdot \ln(2) = ln\left(2^{1/2}\right) = \ln(\sqrt{2})\) It's all in the properties!
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