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ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1361407430942:dw
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
how this gets to \[\ln \sqrt{2}\]
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
@TuringTest
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
i know that so dw:1361408007302:dw
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
You MUST have been given fundamental principles of logarithms, Here's one: log(a) + log(b) = log(a*b) Have you any others?
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
i dont get this
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
this is  so division right
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
Good. log(a)  log(b) = log(a/b) Any more?
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1361408413459:dw
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
so ln(2)/(2)
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
how did they got ln sqrt 2
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
@SithsAndGiggles
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
So, you're saying you have only two properties for logarithms? You don't have this one: \(a\cdot \log(b) = \log\left(b^{a}\right)\)?
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1361408835272:dw where do u use that
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
\(\dfrac{\ln(2)}{2} = \dfrac{1}{2}\cdot \ln(2) = ln\left(2^{1/2}\right) = \ln(\sqrt{2})\) It's all in the properties!
 one year ago
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