A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 one year ago
I need your help!
A charge of 5 x109 C is attracted by a charge of –3x107 C with a force of 0.135 N. How far apart are they? (Hint: manipulate the equation to get an expression for d)
 one year ago
I need your help! A charge of 5 x109 C is attracted by a charge of –3x107 C with a force of 0.135 N. How far apart are they? (Hint: manipulate the equation to get an expression for d)

This Question is Closed

Iamgmg90
 one year ago
Best ResponseYou've already chosen the best response.1Coulombs law \[F = (Q_1\times Q_2)/(4\pi \times \epsilon_0 \times d^2) \]

dhudz23
 one year ago
Best ResponseYou've already chosen the best response.0Could you help me on how to start it?

Shane_B
 one year ago
Best ResponseYou've already chosen the best response.1You just plug in the values you know into the formula and solve for d

Shane_B
 one year ago
Best ResponseYou've already chosen the best response.1\[\large 0.135N = \frac{5x10^{9}C\times 3x10^{7}C}{4(3.14159) \times 8.85x10^{12} \frac{C^2}{Nm^2}\times d^2}\]As the question states, now you must manipulate this equation to solve for d.

dhudz23
 one year ago
Best ResponseYou've already chosen the best response.0Thank you! I think I got it.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.