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 one year ago
let r be the region enclosed by the graph of f(x)=1/x^2 g(x)=e^x and the line x=1 and x=k where k>1 find the limit as k approaches infinity of A(k).
A(k) we derived before and I believe that it is the integral from 1 to k ((1/k)+(E^k))
 one year ago
let r be the region enclosed by the graph of f(x)=1/x^2 g(x)=e^x and the line x=1 and x=k where k>1 find the limit as k approaches infinity of A(k). A(k) we derived before and I believe that it is the integral from 1 to k ((1/k)+(E^k))

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TuringTest
 one year ago
Best ResponseYou've already chosen the best response.1your formula for the area is not quite right

marytheshade
 one year ago
Best ResponseYou've already chosen the best response.0ok i'm not sure what I did wrong

marytheshade
 one year ago
Best ResponseYou've already chosen the best response.0I mean initially it was integral from 1 to k (1/2x^2e^x)dx but when you differentiate wouldn't you get what I got?

TuringTest
 one year ago
Best ResponseYou've already chosen the best response.1you can't take the derivative, the area is a function of the definite integral

marytheshade
 one year ago
Best ResponseYou've already chosen the best response.0woops i meant anti derivative

TuringTest
 one year ago
Best ResponseYou've already chosen the best response.1what do you get after integrating?

marytheshade
 one year ago
Best ResponseYou've already chosen the best response.0Well integrating the equation I got what I said before, ((1/k)+(E^k))...i didn't try to solve it any further

TuringTest
 one year ago
Best ResponseYou've already chosen the best response.1you did not evaluate correctly\[A(x)=\int_1^k\frac1{x^2}e^{x}dx=\left.\frac1x+e^{x}\right_1^k=\left(\frac1k+e^{k}\right)\left(1+\frac1e\right)\]
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