@Surferbumm @fortytwo @Frostbite @rizzu @Reaper534 @evansda @EvonHowell @evergirl @thatgirl666 @Reaper534 @jes230 @Markitos @marcoduuuh @saify_12 anybody know geometry> @dmezzullo @Grazes @anthony~ @samanthastephens702 @pooja195
 anonymous
@Surferbumm @fortytwo @Frostbite @rizzu @Reaper534 @evansda @EvonHowell @evergirl @thatgirl666 @Reaper534 @jes230 @Markitos @marcoduuuh @saify_12 anybody know geometry> @dmezzullo @Grazes @anthony~ @samanthastephens702 @pooja195
 katieb
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 anonymous
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 anonymous
@dumbsearch2 @fortytwo @tthomas0557 @twitch @ghazi @saify_12 @samantharandix @samtab @samtasticc @GYANNYGY @genius12
 anonymous
@joyflow @joannaxox3 @Luis_Rivera @FlaCaLOL @Saphire21 @SavannaLynn. @francis1
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 FlaCaLOL
dont hv tht sorry!!! :/
 anonymous
i have geometry B
 anonymous
so would u know how to help and explain it to me?please..
 anonymous
well i cant make any promises becaue i am not so good at geometry either so yea
 anonymous
its not just about getting the answer...i need a lot of work to catch up on in geom,&BIOACD1, and i can't just know the answer, i need to actually know it and someone explain it
 anonymous
I dont. Sorry.
 anonymous
@bakonloverk @SamGracie @Hoa @gorica @tinaballerina @lillybeth123 @LilHefner3
 anonymous
@trevorttreesh @TrentSuncloud @Jiimy20110 @jasmynarteaga1 @JenniferSmart1 @carlenstar281 @campbell_st anybody?????!!!!!plz
 anonymous
@A_Level_Student @azura @GeekNeko @Para_phrenic88
 anonymous
@ParthKohli @kudrick16 @UmmmHELP @uri @lexiw.dances @LonelyandForgotten @LoPPn @Agent_Sniffles @venom936 @vt
 anonymous
I wish I could help but im really not good at explaining geometry...sorry
 anonymous
@abb0t @idhatetobeyou @Israel936 @ihavemathquestion @NewGeek @Anders96 @anas2000 @onedirection123 @Opcode @fortytwo
 anonymous
@UmmmHELP its ok
 anonymous
@abb0t @idhatetobeyou @Israel936 @ihavemathquestion @NewGeek @Anders96 @anas2000 @onedirection123 @Opcode @fortytwo
@Icewinifredd @OMG3 @Preetha @pleasehelpme432 @PleaseDiscoverMe
 anonymous
@lvasquev462 @Figureskater120 @pleasehelpme432
 anonymous
ok simple
 anonymous
look at the sides which are correspondin
 anonymous
I want us to go step by step can u tell me the sides which are a corresponding plis
 anonymous
idk....!
 anonymous
ok first of all the triangles are similar because they have the same angles
 anonymous
i know that.
 anonymous
cool 10 corresponds with 15
 anonymous
ok...
 anonymous
i would help but i suck at explaining things
 abb0t
OMG.
 anonymous
thanks anyways @joannaxox3
 anonymous
@A_Level_Student continue
 anonymous
so its 10:15
 anonymous
ok
 anonymous
yea sorry i would but im just as bad as you but my brother helps me
 anonymous
simplifying that ratio we get 2:3
 anonymous
we got it by dividing by 5
 anonymous
how would u know what to divide though.
 anonymous
ok if u have 5:10 its the same as (5/10) fractional form so u simplify this fraction by dividing by 5 in numerator and denominator
 anonymous
but how did u know what number to divide though
 anonymous
Sorry, cant help u!
 anonymous
u divide by the highest common factor
 anonymous
5divided by 5 is 1 so then 5divided by 10 =.5
 anonymous
?
 anonymous
sory that's supposed to be 15
 anonymous
ok.
 anonymous
so the ratio is 2:3
smaller:bigger
 anonymous
ok
 anonymous
so u are ok with the first one
 anonymous
yes know i get that...so it would be 2;3
 anonymous
what would i write as the statement?
 anonymous
because it says if they'r similar to write a statement ??
 anonymous
The two triangles are simila in the ration 2:3
 anonymous
number one is yes the ratio is 2/3 because 2/3 x 24 = 16
 anonymous
the two triangles are similar in the ratio 2:3
 anonymous
ok what about the next one.
 anonymous
A corresponds wit D ,B with E and C with F right
 anonymous
i need to understand it too , because i have more of these papers to do.
 anonymous
Now if u look at side AB and side DE ,de have been enlarged
 anonymous
its from 2 boxes to 3 boxes that's 2*x=3
find x
 anonymous
the x will be the scale factor of enlargment
 anonymous
i don't get this @ all...how would i find x,, i know AB and side DE have been enlarged. but what about 2 times x=3,.i don't get how u got what ur ssaying.
 anonymous
@trevorttreesh @TrentSuncloud @geometrysucks @geneticrockhopper247 @kugler97 @overtonka someone help me understand this!
 anonymous
Ab HAS been enlarged from 2boxes to 3 boxes
 anonymous
i need to turn this in today:/!
 anonymous
thanks @A_Level_Student for giving up on me.
 anonymous
anyone else
 anonymous
@countonme123 @Opcode
 anonymous
what ya need @Kitt020912
 anonymous
I suck at geometry so I thought maybe you could help
 anonymous
@countonme123 can u help?!
 anonymous
What is the question? ^_^
 anonymous
#2 on the attachment.
 anonymous
i don't do attachments
 anonymous
ok then.
 anonymous
my pc won't open em up
 anonymous
then just forget it,
 anonymous
sometimes mine wont either @seiga what problems do you still need help with? maybe you can draw them
 anonymous
ya i will help u......i know geometry very well
 anonymous
@Kitt020912 trust me they'r graphs and stuff so i don't think i can.plus im not a good drawer.
 anonymous
i have to turn this in by today.:"
 EvonHowell
you might want to visit mathway.com
 anonymous
i cant do that...i have to actually get it.in my head, not just get the answer but not know how i got it.
 anonymous
Sorry :/
 anonymous
its ok
 anonymous
anyone else?
 anonymous
why am i tagged in this ?
 anonymous
i tagged everyone to see if they can help me with this geo paper.
 anonymous
whats the question
 anonymous
its on the attached file...
 anonymous
the first one i already know...i just need to get the rest.
 anonymous
math is my weakest subject , wish i could help you ! ,sorry hun
 anonymous
its ok.
 anonymous
Woahh, sorry I haven't taken geometry yet!
 anonymous
oh ok
 anonymous
i need to turn in this paper by today,...and im already late, and i can't fail this class!
 anonymous
Which one? oo
 anonymous
number two and the rest of it...i already did number 1...
 anonymous
i skipped geometry class. i never taken it. :/ i looked at the questions and i have no idea how to do any of these ..
 anonymous
For the second one, I think you just reflect triangle ABC over the x axis and dilate, but you'll have to check on that.
 anonymous
Yeah... It's right. The dilation rate is 2/3. You kinda stare at the graph. Congruent transformations include translations, reflects, and rotations. It's not translations or rotations because it it need that specific orientation
 anonymous
The 3rd one is all circles are similar because a circle is a shape created by a set of points that are a constant distance from the center point of the circle.
 anonymous
For 4, you know that there are corresponding angles created by the 2 transversals and the parallel lines. By getting 2 sets of congruent angles, AA~AA
 anonymous
I'm going to assume that you know how to find the lengths
 anonymous
lets just say u shouldn't assume..because i don't know nothing about this !
 anonymous
yeah im in the same as you, im taking a geometry online class & dont understand it very well:(
 anonymous
5. You have parallel lines, so alternate interior angles are congruent. You also have vertical angles congruent so AA~AA. Then, you use the theorum "If two triangles are similar, then the ratio of any two corresponding segments (such as altitudes, medians, or angle bisectors) equals the ratio of any two corresponding sides."
 anonymous
4. (3/x)=(7.5/x+6)
 anonymous
Just make sure you understand it, or a mod/touchy person will beat me with a stick for not making you think.
 anonymous
thanks(:
 anonymous
im not in geometry im n algebra2B
 anonymous
Holy cow.
Hi guys. (;
 anonymous
to question #1 Δ QPR and ΔBAC are similar since they have pairs of angle equal, ∠PQR =∠ABC; ∠QPR =∠BAC and PRQ=∠ACB > they are similar. the ratio is
PQ PR PR AQ AQ 2
 =  and  =  and  = 
AB AC AC BC BC 3
.
you can calculate by replace the length of sides into my equation to figure out that the ratio between them is
2

3
the condition to have that conclusion is you must name the triangles in order makes them similar. if you change the order, you cannot find out the ratio.
. I don't know whether you still need the explanation or not, if it's too late. I'm sorry. My help is out of date.
 anonymous
If you still need help for those question, let me know.
 anonymous
i need to show my work.
 anonymous
and i need to get all of them done, and can u please try to help me with my other bio question paper.
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