help me @Daish96 @dumbsearch2 @damien @Danny_Boy

- anonymous

help me @Daish96 @dumbsearch2 @damien @Danny_Boy

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- anonymous

@countonme123

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- anonymous

omgggggggggg idk

- anonymous

not in that problem

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## More answers

- anonymous

@damien @Daish96 @DLS @dietrich_harmon @Koikkara @kugler97 @Kpinky

- Koikkara

@InYourHead .....

- anonymous

@ThatHippieKid @haleylou56 @heena @hewsmike @hannahbabiexoxo

- anonymous

i really need help

- anonymous

@nincompoop @NickR @nolesgirl328 @nolesgirl328

- anonymous

64b^10/b^9c^5= 64b/c^5

- anonymous

omggggggg confused thats the anwser?????

- anonymous

yes

- anonymous

ummm thanks can u help me with these other 3 questions?

- anonymous

but on one condition u hav to also try with me and have to try to undrstand how towork on such question is it fine?

- anonymous

yeah

- anonymous

)Robert loves football and wants to start practice throwing daily. The first day he practices for 3 minutes. The next day he triples his time. Robert continues to triple his practice time every day. How many minutes did Robert practice on the fourth day?

- anonymous

ok on firt day he did 3^1-3min
den on second day he triples his time mean 3^3=3x3x3=27min

- anonymous

now on third day u tell me

- anonymous

27x3=81

- anonymous

i think triples mean increasing power means 27^3

- anonymous

danya what happen?

- anonymous

27x27x27=19683

- anonymous

???????????????????????

- anonymous

@heena ??????????????????

- anonymous

what dear ? now work for fourth dat imilarly as u did for third day

- anonymous

similaraly

- anonymous

didnt u get the trick how to work on it?

- anonymous

7625597484987

- anonymous

is that right???

- anonymous

@heena

- anonymous

@jonnymiller @Jenn777 @hewsmike @heena @whpalmer4 @Agent_Sniffles @ash2326 @Koikkara @kelliegirl33 is this right

- anonymous

@ash2326 i think i made a mistake help her plz

- anonymous

orry danya but i think i m not correct here

- anonymous

Im so lost lol

- anonymous

the questiopn is at the top

- anonymous

its okay @heena

- ash2326

@danya1 Always ask new question as a new post
Robert loves football and wants to start practice throwing daily. The first day he practices for 3 minutes. The next day he triples his time. Robert continues to triple his practice time every day. How many minutes did Robert practice on the fourth day?

- ash2326

He triples his time means times 3
First day 3 minutes=3 mins
Second 3*3 minutes=9 mins
Can you find for the third day and 4th day?
It's just multiplication :)

- anonymous

yes thats the question

- anonymous

do i do 9x3??

- anonymous

Is this how to do it.....are you sure it doesn't have anything to do with exonents ?
first day = 3 min
2nd day = 3 x 3 = 9
3rd day = 9 x 3 = 27
4th day = 27 x 3 = 81

- anonymous

oops...typo...exponents ?

- ash2326

yes @danya1

- anonymous

or is it 9x9x9

- ash2326

9*3

- anonymous

see...that is what is confusing me....exponents

- anonymous

I suppose ash is right.....we are making this too hard when it isn't.

- ash2326

thrice is 3 times

- anonymous

Thanks for explaining ash....oh, and I am sorry I stepped on your turf...I will do better

- ash2326

no problem @kelliegirl33

- anonymous

you deserve the medal ash :)

- ash2326

Do you get @danya1

- anonymous

so the second day was 9 and the third is 9x3=27 and the fourth day is 27x3=81

- ash2326

Yes @danya1 :D

- anonymous

ash is good

- ash2326

Thanks @kelliegirl33 :)
Likewise :D

- anonymous

can u help me withe the first problem i wrote at the top thanks

- ash2326

Okay, you want to simplify it
\[(\frac{2b^2}{b^4c})^5\]
First cancel the common terms
\[(\frac{2\cancel{b^2}}{b^{\cancel 4 2}c})^5\]
so we get
\[(\frac{2}{b^2c})^5\]
Do you understand till here?

- anonymous

ummmmmmmmmmmmmm yea

- ash2326

Now just raise the terms to the power
\[\frac{2^5}{b^{2^5}c^5}\]
\[\frac{32}{b^{10}c^5}\]

- anonymous

ok thats it

- ash2326

yes

- anonymous

thankswhat about this one

- anonymous

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- ash2326

@danya1 Please close this question and ask this question in a new post :)
That way you'll get help from many users :)

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