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haleyking345 Group Title

tan^2x - tan^2x sin^2x = sin^2x How in the world could you solve this?

  • one year ago
  • one year ago

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  1. TuringTest Group Title
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    \[\tan^2x-\tan^2x\sin^2x=\tan^2x(1-\sin^2x)\]and what is the identity for \(1-\sin^2x\) ?

    • one year ago
  2. haleyking345 Group Title
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    cos^2x

    • one year ago
  3. TuringTest Group Title
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    right, so now what do you have on the left?

    • one year ago
  4. haleyking345 Group Title
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    tan^2x-tan^2xsin^2x=tan^2x

    • one year ago
  5. TuringTest Group Title
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    no, I mean after what we just did...

    • one year ago
  6. haleyking345 Group Title
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    tan^2x

    • one year ago
  7. TuringTest Group Title
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    \[\tan^2x-\tan^2x\sin^2x=\tan^2x(1-\sin^2x)=\tan^2x\cos^2x=?\]

    • one year ago
  8. TuringTest Group Title
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    use\[\tan x=\frac{\sin x}{\cos x}\]

    • one year ago
  9. haleyking345 Group Title
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    that would leave you with sin^2x as the answer

    • one year ago
  10. TuringTest Group Title
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    which is what you have on the left, which proves the identity if you want a solution, the answer is \(\mathbb R\), but I think the point here was just to prove the identity.

    • one year ago
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