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You're first step should be to draw the angle on the coordinate plane.

@alanli123
Fatal Error :P
It's
sin² x = 1 - cos² x
You used
sin x = 1 - cos² x

Quadrant 2

And...? There's another.

oh quadrant 3

Quadrant 3 right?

Correct. So let's draw our triangle in quadrant 3...
|dw:1361494367065:dw|

Now, the cosine of the angle is -2/3... how do you figure that into your triangle?

put -2 on x-axis line and 3 on the longest side

is it square root of 5?

should it be - square root of 5?

Yes. it should :P
So far, is everything clear to you? :)
|dw:1361494965439:dw|

yes it is

- sqrt 5/3

3/ -sqrt 5

tangent of the *angle
sorry

sqrt 5/2

2/sqrt 5 or 2sqrt 5/5

ok that makes sense. thank you very much!!!

No problem :)

Need to go now, anyway :D
----------------------
Terence out