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Pologirl19

simplify the sum d^2-9d+20 / d^2-3d-10 + d^2-2d-8 / d^2+4d-32

  • one year ago
  • one year ago

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  1. Pologirl19
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    \[\frac{ d^2 - 9d + 20 }{ d^2 - 3d -10 } + \frac{ d^2 - 2d - 8 }{ d^2 + 4d - 32 }\]

    • one year ago
  2. Pologirl19
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    Help please

    • one year ago
  3. zepdrix
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    Ok looks like we have to do some factoring :) Hmm let's look at it piece by piece.\[\large \frac{\color{orangered}{d^2-9d+20}}{\color{green}{d^2-3d-10}}+\frac{\color{royalblue}{d^2-2d-8}}{\color{purple}{d^2+4d-32}}\]Let's look at the green portion first.

    • one year ago
  4. zepdrix
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    We want `factors` of -10, that `add` to form -3. Hmm let's try \(-10\) and \(1\). \(-10\cdot1=-10\) ok good, but if we try to add them, \(-10+1\neq-3\). Hmm ok those factors won't work. Can you think of any other factors of -10? :)

    • one year ago
  5. summer1980
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    \[\frac{ (d-5)(d-4) }{ (d-5)(d+2)}+\frac{ (d-4)(d+2) }{ (d-4)(d+8)}=\frac{ d-4 }{ d+2}+\frac{ d+2 }{ d+8}\] i hope this helps

    • one year ago
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