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willowdavis97
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What is the pH of a solution that has a concentration of hydronium ions that is 1.8 × 104 M OH? Show, or explain, the work used to solve this problem.
 one year ago
 one year ago
willowdavis97 Group Title
What is the pH of a solution that has a concentration of hydronium ions that is 1.8 × 104 M OH? Show, or explain, the work used to solve this problem.
 one year ago
 one year ago

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willowdavis97 Group TitleBest ResponseYou've already chosen the best response.0
makes no sense I have no idea how to do this
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
pOH = log[OH] pH + pOH =14
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
you meant hydroxide ions, right?
 one year ago

willowdavis97 Group TitleBest ResponseYou've already chosen the best response.0
I don't so that was the exact question.
 one year ago

willowdavis97 Group TitleBest ResponseYou've already chosen the best response.0
Is there a formula? I could do it if I had one.
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
in your question, you said hydronium but then you wrote OH, which one is it?
 one year ago

willowdavis97 Group TitleBest ResponseYou've already chosen the best response.0
I think the () is supposed to be up higher if that makes a difference. 1.8 × 10^4 M OH^
 one year ago

willowdavis97 Group TitleBest ResponseYou've already chosen the best response.0
I guess that makes no sense at all
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
lol no i understand that part.. but hydronium = H3O+ and hydroxide OH so it's hydroxide? lol i'm just confused b/c you said two different things and one or the other completely changes the answer
 one year ago

willowdavis97 Group TitleBest ResponseYou've already chosen the best response.0
Well the question it asked me was that so i dont know if its right or not :(
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
there must be a type somewhere if it's 1.8 × 10^4 M OH^ .. use the equations i gave you first if it's 1.8 × 10^4 M H3O+ then just use pH= log[H3O+]
 one year ago

willowdavis97 Group TitleBest ResponseYou've already chosen the best response.0
what do I put into the equation. Whats a log Ahhh sorry I sound so stupid I suck so bad at chemistry :(
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
you input the number.. 1.8 × 10^4 or 0.00018 then press log on your calculator .. which turns into a logarithm base 10 then press the negative sign
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
lol it's cool, everyone's gotta learn someday, no one is born with this knowledge
 one year ago

willowdavis97 Group TitleBest ResponseYou've already chosen the best response.0
okay I did that I got  3.74472749..... Does that sound right?
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
you didn't press the negative sign, it's supposed to be 3.74 if it was a negative number it would be very very acidic
 one year ago

willowdavis97 Group TitleBest ResponseYou've already chosen the best response.0
Ohhhh, okay. Does that mean the ph is 3.74..?
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
if the concentration they gave you was in H3O+ ions, if it was OH you have to subtract from 14
 one year ago

willowdavis97 Group TitleBest ResponseYou've already chosen the best response.0
okay so 143.74? so 10.26
 one year ago

willowdavis97 Group TitleBest ResponseYou've already chosen the best response.0
Thank you!
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
no problem !
 one year ago
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