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hint :
-5^(log[5] 1 = -1
now, setting -1 be log[3] (1/3)

HINT(also): \(\large log_327=a \Leftrightarrow 3^a=27 \)
what's a= ???

a=3? D:

yes, that's right.. then, ?

* log[3] (x-2)(x-4)/27= log [3] (1/3)

*forgot to put log[3]

no, i have used the property of logarithm :
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