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Kilochan
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log[3](x2)=log[3] 27  log[3](x4) 5^(log[5]1)
I have tried this out and right now all I am getting is
log[3] (x2)(x4)/27= 5^(log[5] 1)
Is this somewhat right so far? I'm not sure what to do with the "log[3] 27"
the answer is supposed to be 3+sqrt(10)
 one year ago
 one year ago
Kilochan Group Title
log[3](x2)=log[3] 27  log[3](x4) 5^(log[5]1) I have tried this out and right now all I am getting is log[3] (x2)(x4)/27= 5^(log[5] 1) Is this somewhat right so far? I'm not sure what to do with the "log[3] 27" the answer is supposed to be 3+sqrt(10)
 one year ago
 one year ago

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RadEn Group TitleBest ResponseYou've already chosen the best response.1
hint : 5^(log[5] 1 = 1 now, setting 1 be log[3] (1/3)
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.0
HINT(also): \(\large log_327=a \Leftrightarrow 3^a=27 \) what's a= ???
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.1
yes, that's right.. then, ?
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.1
well, i want make easier for u from ur solution above : log[3] (x2)(x4)/27= 5^(log[5] 1 setting right side be 1 it can be : log[3] (x2)(x4)/27= 1 then 1 = [3] (1/3), therefore it can be log[3] (x2)(x4)/27= [3] (1/3) cancel out the log[3] to both sides (x2)(x4)/27= 1/3 or (x2)(x4) = 27 * 1/3 (x2)(x4) = 9 now, solve for x
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.1
* log[3] (x2)(x4)/27= log [3] (1/3)
 one year ago

Kilochan Group TitleBest ResponseYou've already chosen the best response.0
Ok! I was close. I for for to put log[3] on both sides. But now that I see where I went wrong, I will finish solving for x and let you know if I have any problems. Thank you so much for your help!
 one year ago

Kilochan Group TitleBest ResponseYou've already chosen the best response.0
*forgot to put log[3]
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.1
okay... to get solution of (x2)(x4) = 9 simplify, frist. then use quadratic formuka : x = {b + sqrt(b^24ac)}/2a if u got 2 solution's, that one positive and the other negative, just take that positive value, because for x negative undefined for log[3] (x2)
 one year ago

Kilochan Group TitleBest ResponseYou've already chosen the best response.0
I finished the problem! I got the correct answer! Thanks for your help! One last question. for 5^(log[5] 1, did you plug that in a calculator? I tried that and I'm getting the number 3.
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.1
no, i have used the property of logarithm : dw:1361529157735:dw
 one year ago
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