Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Kilochan Group Title

log[3](x-2)=log[3] 27 - log[3](x-4) -5^(log[5]1) I have tried this out and right now all I am getting is log[3] (x-2)(x-4)/27= -5^(log[5] 1) Is this somewhat right so far? I'm not sure what to do with the "log[3] 27" the answer is supposed to be- 3+sqrt(10)

  • one year ago
  • one year ago

  • This Question is Closed
  1. RadEn Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    hint : -5^(log[5] 1 = -1 now, setting -1 be log[3] (1/3)

    • one year ago
  2. ByteMe Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    HINT(also): \(\large log_327=a \Leftrightarrow 3^a=27 \) what's a= ???

    • one year ago
  3. Kilochan Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    a=3? D:

    • one year ago
  4. RadEn Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yes, that's right.. then, ?

    • one year ago
  5. RadEn Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    well, i want make easier for u from ur solution above : log[3] (x-2)(x-4)/27= -5^(log[5] 1 setting right side be -1 it can be : log[3] (x-2)(x-4)/27= -1 then -1 = [3] (1/3), therefore it can be log[3] (x-2)(x-4)/27= [3] (1/3) cancel out the log[3] to both sides (x-2)(x-4)/27= 1/3 or (x-2)(x-4) = 27 * 1/3 (x-2)(x-4) = 9 now, solve for x

    • one year ago
  6. RadEn Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    * log[3] (x-2)(x-4)/27= log [3] (1/3)

    • one year ago
  7. Kilochan Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Ok! I was close. I for for to put log[3] on both sides. But now that I see where I went wrong, I will finish solving for x and let you know if I have any problems. Thank you so much for your help!

    • one year ago
  8. Kilochan Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    *forgot to put log[3]

    • one year ago
  9. RadEn Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    okay... to get solution of (x-2)(x-4) = 9 simplify, frist. then use quadratic formuka : x = {-b +- sqrt(b^2-4ac)}/2a if u got 2 solution's, that one positive and the other negative, just take that positive value, because for x negative undefined for log[3] (x-2)

    • one year ago
  10. Kilochan Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    I finished the problem! I got the correct answer! Thanks for your help! One last question. for -5^(log[5] 1, did you plug that in a calculator? I tried that and I'm getting the number 3.

    • one year ago
  11. RadEn Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    no, i have used the property of logarithm : |dw:1361529157735:dw|

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.