Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

MindyMcT

  • 3 years ago

What volume of 2.25M NaCl solution is required to react completely with 1.00L of 0.750M Pb(NO3) solution? Pb(NO3)2(aq)+2NaCl(aq)=PbCl2(s)+2NaNO3(aq)

  • This Question is Closed
  1. .Sam.
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    You need to find the volume of NaCl, based from formula \[[M]=\frac{mol}{V}\]

  2. .Sam.
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    They have given some values for Pb(NO3) right, so using that formula, \[[M]=\frac{mol}{V}\] mol=MV n(Pb(NO3)) = (0.750)(1.00) = 0.750moles of Pb(NO3) According to the equation, Pb(NO3)2(aq)+2NaCl(aq)=PbCl2(s)+2NaNO3(aq) 1 Pb(NO3)2 is equivalent to 2 NaCl, so 0.750 times 2 = 1.5 moles of NaCl then use back the equation \[[M]=\frac{mol}{V}\] \[V=\frac{mol}{[M]}\] \[V=\frac{1.5}{2.25}=0.667 m^3\]

  3. MindyMcT
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ok thank you so much! You just cleared up the M to mol to V formula for me. I was getting stumped using M to get to other values. All I knew was that M=mol/L Thank you for your help.This was the last practice problem I couldn't figure out. I might actually be ready for this quiz today now!

  4. Vincent-Lyon.Fr
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    0.667 m3 is a lot!

  5. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy