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UnkleRhaukus Group Title

@azooo "Two electrons are separated by 1 meter. What is the ratio of the magnitude of the electric force on one electron and the gravitational force on that electron due to the other electron? The charge of an electron is 1.6*10^-19C and its mass is 9.1*10^-31?? which formuA will use for it?? "

  • one year ago
  • one year ago

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  1. Mashy Group Title
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    which are the formulae you know to calculate the force of gravity between two point masses? and electric force between 2 point charges? :P

    • one year ago
  2. UnkleRhaukus Group Title
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    \[\begin{align*}\left|\frac{\vec{\mathbf F}_{\text{electric}}}{\vec{\mathbf{F}}_{\text{gravitational}}}\right| &=\frac{K\dfrac{q_{e^-}q_{e^-}}{d^2}}{G\dfrac{m_{e^-}m_{e^-}}{d^2}} % =\frac KG\left( \frac{q_{p}}{m_{p}}\right)^2 \\ %&=\frac{9.0\times10^9 \left[\frac{\text N\cdot\text m^2}{\text C^2}\right]} %{6.7\times10^{-11}\left[\frac{\text{N}\cdot\text m^2}{\text {kg}^2}\right]} %\left(\frac{1.6\times10^{-19}[\text C]}{1.7\times10^{-27}[\text{kg}]}\right)^2 \\ %&=\left(\frac{9.0\times1.6^2}{6.7\times1.7^2}\right)\frac{10^{9-2\times19}}{10^{-11-2\times27}} \\ %&=\left(\frac{9.0\times2.56}{6.7\times2.89}\right)\frac{10^{-9-2\times19}}{10^{-11-54}} \\ %&=1.2\times10^{-29+65} \\ %&=1.2\times10^{36} \end{align*} \]

    • one year ago
  3. Mashy Group Title
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    there you go!!.. so whats the problem ?

    • one year ago
  4. UnkleRhaukus Group Title
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    for the rato of the forces between Protons \[\begin{align*} \left|\frac{\vec{\mathbf F}_{\text{electric}}}{\vec{\mathbf{F}}_{\text{gravitational}}}\right| &=\frac{K\dfrac{q_{p}q_{p}}{d^2}}{G\dfrac{m_{p}m_{p}}{d^2}} =\frac KG\left( \frac{q_{p}}{m_{p}}\right)^2 \\ &=\frac{9.0\times10^9 \left[\frac{\text N\cdot\text m^2}{\text C^2}\right]} {6.7\times10^{-11}\left[\frac{\text{N}\cdot\text m^2}{\text {kg}^2}\right]} \left(\frac{1.6\times10^{-19}[\text C]}{1.7\times10^{-27}[\text{kg}]}\right)^2 \\ %&=\left(\frac{9.0\times1.6^2}{6.7\times1.7^2}\right)\frac{10^{9-2\times19}}{10^{-11-2\times27}} \\ &=\left(\frac{9.0\times2.56}{6.7\times2.89}\right)\frac{10^{-9-2\times19}}{10^{-11-54}} \\ %&=1.2\times10^{-29+65} \\ &=1.2\times10^{36} \end{align*}\]

    • one year ago
  5. UnkleRhaukus Group Title
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    notice how the distance cancels out,

    • one year ago
  6. azooo Group Title
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    thank u

    • one year ago
  7. Mashy Group Title
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    oh lol you opened this question to explain it to someone lol.. sorry :D

    • one year ago
  8. UnkleRhaukus Group Title
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    can close the question now @azooo ?

    • one year ago
  9. azooo Group Title
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    yes thank u

    • one year ago
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