Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

UnkleRhaukus

  • one year ago

@azooo "Two electrons are separated by 1 meter. What is the ratio of the magnitude of the electric force on one electron and the gravitational force on that electron due to the other electron? The charge of an electron is 1.6*10^-19C and its mass is 9.1*10^-31?? which formuA will use for it?? "

  • This Question is Closed
  1. Mashy
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    which are the formulae you know to calculate the force of gravity between two point masses? and electric force between 2 point charges? :P

  2. UnkleRhaukus
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    \[\begin{align*}\left|\frac{\vec{\mathbf F}_{\text{electric}}}{\vec{\mathbf{F}}_{\text{gravitational}}}\right| &=\frac{K\dfrac{q_{e^-}q_{e^-}}{d^2}}{G\dfrac{m_{e^-}m_{e^-}}{d^2}} % =\frac KG\left( \frac{q_{p}}{m_{p}}\right)^2 \\ %&=\frac{9.0\times10^9 \left[\frac{\text N\cdot\text m^2}{\text C^2}\right]} %{6.7\times10^{-11}\left[\frac{\text{N}\cdot\text m^2}{\text {kg}^2}\right]} %\left(\frac{1.6\times10^{-19}[\text C]}{1.7\times10^{-27}[\text{kg}]}\right)^2 \\ %&=\left(\frac{9.0\times1.6^2}{6.7\times1.7^2}\right)\frac{10^{9-2\times19}}{10^{-11-2\times27}} \\ %&=\left(\frac{9.0\times2.56}{6.7\times2.89}\right)\frac{10^{-9-2\times19}}{10^{-11-54}} \\ %&=1.2\times10^{-29+65} \\ %&=1.2\times10^{36} \end{align*} \]

  3. Mashy
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    there you go!!.. so whats the problem ?

  4. UnkleRhaukus
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    for the rato of the forces between Protons \[\begin{align*} \left|\frac{\vec{\mathbf F}_{\text{electric}}}{\vec{\mathbf{F}}_{\text{gravitational}}}\right| &=\frac{K\dfrac{q_{p}q_{p}}{d^2}}{G\dfrac{m_{p}m_{p}}{d^2}} =\frac KG\left( \frac{q_{p}}{m_{p}}\right)^2 \\ &=\frac{9.0\times10^9 \left[\frac{\text N\cdot\text m^2}{\text C^2}\right]} {6.7\times10^{-11}\left[\frac{\text{N}\cdot\text m^2}{\text {kg}^2}\right]} \left(\frac{1.6\times10^{-19}[\text C]}{1.7\times10^{-27}[\text{kg}]}\right)^2 \\ %&=\left(\frac{9.0\times1.6^2}{6.7\times1.7^2}\right)\frac{10^{9-2\times19}}{10^{-11-2\times27}} \\ &=\left(\frac{9.0\times2.56}{6.7\times2.89}\right)\frac{10^{-9-2\times19}}{10^{-11-54}} \\ %&=1.2\times10^{-29+65} \\ &=1.2\times10^{36} \end{align*}\]

  5. UnkleRhaukus
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    notice how the distance cancels out,

  6. azooo
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thank u

  7. Mashy
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh lol you opened this question to explain it to someone lol.. sorry :D

  8. UnkleRhaukus
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    can close the question now @azooo ?

  9. azooo
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes thank u

  10. Not the answer you are looking for?
    Search for more explanations.

    Search OpenStudy
    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.