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rosedewittbukater

  • one year ago

Help please? Write a rational function with no vertical asymptotes and no holes. Explain. I was thinking x/x^2+1 but I can't tell if it has a vertical asymptote.

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  1. getusel
    • one year ago
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    yes you are absolutely right

  2. rosedewittbukater
    • one year ago
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    @getusel How can I know is there's an asymptote? Those confuse me.

  3. getusel
    • one year ago
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    find the roots of the denominator

  4. rosedewittbukater
    • one year ago
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    Also I thought it doesn't have any zeros, but now I'm thinking it might.

  5. getusel
    • one year ago
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    if the denominator of the rational expression has a solution, it has asymptotes.if not it does not have one.

  6. getusel
    • one year ago
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    the roots should be real number

  7. rosedewittbukater
    • one year ago
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    Does this denominator have one?

  8. getusel
    • one year ago
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    it does not have a real solution for the denominator. This implies that it does not have any.

  9. rosedewittbukater
    • one year ago
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    How would I know if it had a vertical asymptote? Something about when you find the zeros, it can't have a common zero with the nominator. I don't think the function can be factored any more so would this be the right answer?

  10. rosedewittbukater
    • one year ago
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    Did I just say nominator? I meant numerator lol.

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