rosedewittbukater
  • rosedewittbukater
Help please? Write a rational function with no vertical asymptotes and no holes. Explain. I was thinking x/x^2+1 but I can't tell if it has a vertical asymptote.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
yes you are absolutely right
rosedewittbukater
  • rosedewittbukater
@getusel How can I know is there's an asymptote? Those confuse me.
anonymous
  • anonymous
find the roots of the denominator

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rosedewittbukater
  • rosedewittbukater
Also I thought it doesn't have any zeros, but now I'm thinking it might.
anonymous
  • anonymous
if the denominator of the rational expression has a solution, it has asymptotes.if not it does not have one.
anonymous
  • anonymous
the roots should be real number
rosedewittbukater
  • rosedewittbukater
Does this denominator have one?
anonymous
  • anonymous
it does not have a real solution for the denominator. This implies that it does not have any.
rosedewittbukater
  • rosedewittbukater
How would I know if it had a vertical asymptote? Something about when you find the zeros, it can't have a common zero with the nominator. I don't think the function can be factored any more so would this be the right answer?
rosedewittbukater
  • rosedewittbukater
Did I just say nominator? I meant numerator lol.

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