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Emily778
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x = 10 sqrt 3, y = 30
x = 10, y = 30 sqrt 3
x = 30 sqrt 3, y = 10
x = 30, y = 10 sqrt 3
 one year ago
 one year ago
Emily778 Group Title
x = 10 sqrt 3, y = 30 x = 10, y = 30 sqrt 3 x = 30 sqrt 3, y = 10 x = 30, y = 10 sqrt 3
 one year ago
 one year ago

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mathstudent55 Group TitleBest ResponseYou've already chosen the best response.0
The ratio of the lengths of the sides of a 306090 triangle is: short leg : long leg : hypotenuse = 1 : sqrt(3) : 2 The short leg is half the length of the hypotenuse. The long leg is sqrt(3) times longer than the short leg. The hypotenuse here is 20sqrt(3). Half of that is the short leg. Once you have the short leg, multiply it by sqrt(3) to get the long leg.
 one year ago

Outkast3r09 Group TitleBest ResponseYou've already chosen the best response.0
you are looking for adjacent side x since it is next to the angle 30. You're given a hypotenuse. Thinking about relating the hypotenuse, adjacent, and the theta of your angle and SOH CAH TOA.. cosine relates the angle, adjacent sid and hypotenuse using \[cos(\theta)=\frac{Adjacent}{Hypotenuse}\] since you want to solve for the adjacent side, solve for adjacent by multiplying both sides by the hypotenuse \[Hypotenuse*cos(\theta)=\frac{Adjacent}{Hypotenuse}*Hypotenuse\] on the rightside hypotenuse cancel so you're left with \[Hypotenuse*cos(\theta)=Adjacent\]
 one year ago

Outkast3r09 Group TitleBest ResponseYou've already chosen the best response.0
so if you take the hypotenuse( the angle opposite of your right angle and multiply it the cos of your angle 30, you'll get x. I hope this helps ;)
 one year ago
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