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abc12313

  • 3 years ago

Find the exact value of sin (arccos (3/5)). For full credit, explain your reasoning.

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  1. myininaya
    • 3 years ago
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    So if we have x=arccos(3/5) then cos(x)=3/5. Draw a right triangle and use cos(x)=3/5 to find the other missing leg. then evaluate sin(x)

  2. calmat01
    • 3 years ago
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    Myininaya has it down, abc. You should follow myininaya's hint.

  3. abc12313
    • 3 years ago
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    im sorry i still dont understand it could you explain it more? like is it like pythagorean therom?

  4. calmat01
    • 3 years ago
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    Exactly. recall that cosx is just adjacent over the hypotenuse. So, your adj side is 3 and your hypotenuse is 5. Now just find the missing side by applying pythagorean's theorem and then go back and answer your question.

  5. abc12313
    • 3 years ago
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    would it be 4/5?

  6. phi
    • 3 years ago
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    yes For full credit, explain your reasoning.

  7. abc12313
    • 3 years ago
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    I drew a right triangle I used cos(x)=3/5 to find the other missing leg. I know that cosx is just adjacent over the hypotenuse. So, the adj side is 3 and your hypotenuse is 5. I found the missing side by applying pythagorean's theorem and my answer is 4/5

  8. abc12313
    • 3 years ago
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    @phi is this a good answer?

  9. phi
    • 3 years ago
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    yes, sounds good (but I would leave out the "just" in "just adjacent over hypotenuse" I found the missing side by applying pythagorean's theorem I would add "and it is 4" then add the definition of the sin: opposite over adjacent

  10. abc12313
    • 3 years ago
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    okay thank you so much everyone for all of your help!!!

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