anonymous
  • anonymous
Find the exact value of sin (arccos (3/5)). For full credit, explain your reasoning.
Mathematics
chestercat
  • chestercat
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myininaya
  • myininaya
So if we have x=arccos(3/5) then cos(x)=3/5. Draw a right triangle and use cos(x)=3/5 to find the other missing leg. then evaluate sin(x)
anonymous
  • anonymous
Myininaya has it down, abc. You should follow myininaya's hint.
anonymous
  • anonymous
im sorry i still dont understand it could you explain it more? like is it like pythagorean therom?

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anonymous
  • anonymous
Exactly. recall that cosx is just adjacent over the hypotenuse. So, your adj side is 3 and your hypotenuse is 5. Now just find the missing side by applying pythagorean's theorem and then go back and answer your question.
anonymous
  • anonymous
would it be 4/5?
phi
  • phi
yes For full credit, explain your reasoning.
anonymous
  • anonymous
I drew a right triangle I used cos(x)=3/5 to find the other missing leg. I know that cosx is just adjacent over the hypotenuse. So, the adj side is 3 and your hypotenuse is 5. I found the missing side by applying pythagorean's theorem and my answer is 4/5
anonymous
  • anonymous
@phi is this a good answer?
phi
  • phi
yes, sounds good (but I would leave out the "just" in "just adjacent over hypotenuse" I found the missing side by applying pythagorean's theorem I would add "and it is 4" then add the definition of the sin: opposite over adjacent
anonymous
  • anonymous
okay thank you so much everyone for all of your help!!!

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