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Evaluate the Intergal

Mathematics
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\[\int\limits_{}^{}\frac{ 2x^4-4x^3+13x^2-6x+10 }{ (x-2)(x^2-2x+5)^2 }dx\]
I solved it using a beastly amount of partial fractions after solving a system of 5 equations. Please tell me there is another easier way.
jus divide the numerator by x-2

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Why though? I have no reason to do long division.
it is jus to simplify the question
Hmm Okay... Let me see...
Yep. it simplifies, reducing your amount of work.
ok, maybe not. I really need a break. Making too many mistakes today. See you all later.
Erm... THat doesent help O_o . I get: \[2x^3+13x+20 +\frac{ 50 }{ 2x^3+13x+20 }\]
no it doesn't simplify but it has been cooked so that the partial fractions are nice integers
yeah ^ he's right
Ohh they are nice and all but even evaluating the damn partial fractions takes forever.
there are some snap methods for getting some of them i think eliasaab who i have not seen here for a while had a snappy way of doing it
So after the decomposition I get: \[\int\limits_{}^{}\frac{ 2 }{ x-2 }+\frac{ 4 }{ x^2-2x+5 }+\frac{ x }{ (x^2-2x+5)^2 }dx\]
The first term is fine. It's the other two that take forever to integrate.
all integration is a useless pain in the butt that is why they invented computers it is not math, it is wasted doodling
Wolfram made I think... 9 substitutions. I refuse to do that.
@satellite73 D: blasphemy, integration is an art form!
art who?
waste a bunch of time showing off, saying "oh look, can find a function whose derivative is this, and a function whose derivative is that" when the truth is that if you pick a function out of a hat the probability you can find a nice closed for for the anti derivative is zero!
I mean I got the correct answer. But isn't there an easier way to do this?
nope you can see that by how annoying your answer is
Damn it. Thanks anyways guys :)
haha, true that. PF is just plain annoying

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