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completeidiot
 one year ago
Best ResponseYou've already chosen the best response.0are you allowed to use lhopital?

TuringTest
 one year ago
Best ResponseYou've already chosen the best response.3everybody jumps for l'hospital... that should really be a last resort

TuringTest
 one year ago
Best ResponseYou've already chosen the best response.3is this\[\lim_{x\to0}{1\cos^6x\over x\sin^5x}\]?

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0I think it would make this easier to use l'hopitals rule for this on an exam though, just to save time.

TuringTest
 one year ago
Best ResponseYou've already chosen the best response.3Often you are not allowed to use l'hospital if the problem is\[\lim_{x\to0}{1\cos(6x)\over x\sin(5x)}\]it can be solved fairly easily without l'hospital. so far, however, @tamiashi has not replied to me, so I don't want to go ahead with either until I get a response.

tamiashi
 one year ago
Best ResponseYou've already chosen the best response.0Sorry for being late in response, I'm not allowed to use L'hospital Can you show me how to solve it without L'hospital?

TuringTest
 one year ago
Best ResponseYou've already chosen the best response.3is it the first way I wrote it or the second? are 5 and 6 exponents, or coefficients of the argument?

TuringTest
 one year ago
Best ResponseYou've already chosen the best response.3first multiply by\[\frac{1+\cos(6x)}{1+\cos(6x)}\]

TuringTest
 one year ago
Best ResponseYou've already chosen the best response.3you then have\[{1\cos^2(6x)\over x\sin(5x)(1+\cos(6x))}=\frac{1\cos^2(6x)}{x}\cdot\frac1{\sin(5x)}\cdot\frac1{1+\cos(6x)}\]now multiply by \(\frac xx\) to get\[{1\cos^2(6x)\over x\sin(5x)(1+\cos(6x))}=\frac{1\cos^2(6x)}{x^2}\cdot\frac x{\sin(5x)}\cdot\frac1{1+\cos(6x)}\] manipluate this through trig identities and algebra sp that you can utilize\[\lim_{x\to0}\frac{\sin x}x=1\]to get your answer.

tamiashi
 one year ago
Best ResponseYou've already chosen the best response.0okay got it now, thank you so much ^^

RadEn
 one year ago
Best ResponseYou've already chosen the best response.0alternative : use the identity : sin^2 (3x) = (1cos(6x))/2 > 1  cos(6x) = 2 sin^2 (3x) so, it can be : dw:1361606909900:dw
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