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 2 years ago
a) The vector in the opposite direction to u=<5,−1> and of half its length is??
b) The vector of length 10 and in the same direction as v=<4,−5> is
 2 years ago
a) The vector in the opposite direction to u=<5,−1> and of half its length is?? b) The vector of length 10 and in the same direction as v=<4,−5> is

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wio
 2 years ago
Best ResponseYou've already chosen the best response.0What don't you understand about the problem?

abc123!
 2 years ago
Best ResponseYou've already chosen the best response.0i don't know where to start or end

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.0think about the point (5,1) how can we find the opposite direction?

abc123!
 2 years ago
Best ResponseYou've already chosen the best response.0can u just give me the answer

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.0if i go to the right 5 and down 1, the opposite of that would be to go to the left 5 and up 1

abc123!
 2 years ago
Best ResponseYou've already chosen the best response.0can u please just give me the answer

Fosterthepeople
 2 years ago
Best ResponseYou've already chosen the best response.0its B now go to bed

abc123!
 2 years ago
Best ResponseYou've already chosen the best response.0just answer the stupid question

Fosterthepeople
 2 years ago
Best ResponseYou've already chosen the best response.0i said its B NOW GO TO BED

abc123!
 2 years ago
Best ResponseYou've already chosen the best response.0no. a and b are seperate questions. u need to find the vectors that fit the descriptions. idiot

viniterranova
 2 years ago
Best ResponseYou've already chosen the best response.0What do you do when you have to divide something by half?? You can multiply by 1/2.

Fosterthepeople
 2 years ago
Best ResponseYou've already chosen the best response.0abc you wanna change the tone? also we could report you for spamming. Do the pellet yourself

viniterranova
 2 years ago
Best ResponseYou've already chosen the best response.0If you want a opposite vector just multiply by 1.
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