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zenai Group TitleBest ResponseYou've already chosen the best response.0
I'd say 6 personally, but I don't know how to calculate that to be honest.
 one year ago

Megan_xoxo Group TitleBest ResponseYou've already chosen the best response.0
@jim_thompson5910
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
d = sqrt(s^2 + s^2 + s^2) d = sqrt(6^2 + 6^2 + 6^2) d = ???
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
this is an extension of the pythagorean theorem from the 2D version to the 3D version
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
if you don't have a calculator, then you can use google as one http://www.google.com/search?hl=&q=sqrt%286^2+%2B+6^2+%2B+6^2%29+&sourceid=navclientff&rlz=1B3GGLL_enUS420US420&ie=UTF8
 one year ago

viniterranova Group TitleBest ResponseYou've already chosen the best response.1
First consider calculating the Diagonal of the plane on the top of the squared.
 one year ago

viniterranova Group TitleBest ResponseYou've already chosen the best response.1
dw:1361590510885:dw
 one year ago

zenai Group TitleBest ResponseYou've already chosen the best response.0
@viniterranova that value would just be 6sqrt2 which is rounded to 6, that's what I based my answer off of.
 one year ago

viniterranova Group TitleBest ResponseYou've already chosen the best response.1
After found the diagonal of the top´s cube, then use it to calculate the bottom´s diagonal cube.
 one year ago

viniterranova Group TitleBest ResponseYou've already chosen the best response.1
dw:1361591811415:dw
 one year ago

zenai Group TitleBest ResponseYou've already chosen the best response.0
ahh clever, you use pythagorean theorem again to get the third angle, cool!
 one year ago

Megan_xoxo Group TitleBest ResponseYou've already chosen the best response.0
okay thanks guys (:
 one year ago

viniterranova Group TitleBest ResponseYou've already chosen the best response.1
Be my guest.
 one year ago
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