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anonymous
 3 years ago
Calculate the mass of iron metal (in grams) that can be prepared from 150 grams of aluminum and 250 grams of iron(III) oxide.
anonymous
 3 years ago
Calculate the mass of iron metal (in grams) that can be prepared from 150 grams of aluminum and 250 grams of iron(III) oxide.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[ {F}e_2O_3+2Al\implies Al_2O_3+2Fe\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.02Al is the limiting reagent right

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0did you check to see?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0novice in chem,well i just looked at the atom it has 2 moles and Fe2O3 has 1 so yeah

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0to figure out which is limiting you want to to take Grams of reactant >mols of reactant>moles of product with both... which ever can make the least amount of moles of product is your limiting reactant

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Fe2O3 M=55 m=250 n=4.5 Al M=26 m=150 n=5.7

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0alright and then there is 2 aluminum molecules per 2 iron

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so you cna make 9.16 moles of iron with 9.16 moles of aluminum

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0wait 9.6 was error i took wrong mass Al n=5.7

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0o wait nvm 5.7 molecules of aluminum can make 5.7 molecules for iron

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0however per each iron oxide molecule you can make 2 iron oxide molecules

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so multiply 4.5*2 =9 moles of iron.... since you can only make 5.7 moles with the aluminum , Al is your limiting reagent

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now just change 5.7 moles of Fe to grams

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so that would be your answer

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so cant we say there 2Al n=5.7 but 2 moles n=2(5.7)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0answer not correct i think i made a mistake

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the periodic table i am using says atomic weight =Al M=26g/mol is this the right thing to use as M

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0174.85 s the answer thanks
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