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Jonask
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Calculate the mass of iron metal (in grams) that can be prepared from 150 grams of aluminum and 250 grams of iron(III) oxide.
 one year ago
 one year ago
Jonask Group Title
Calculate the mass of iron metal (in grams) that can be prepared from 150 grams of aluminum and 250 grams of iron(III) oxide.
 one year ago
 one year ago

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Jonask Group TitleBest ResponseYou've already chosen the best response.0
\[ {F}e_2O_3+2Al\implies Al_2O_3+2Fe\]
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
2Al is the limiting reagent right
 one year ago

Outkast3r09 Group TitleBest ResponseYou've already chosen the best response.1
did you check to see?
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
novice in chem,well i just looked at the atom it has 2 moles and Fe2O3 has 1 so yeah
 one year ago

Outkast3r09 Group TitleBest ResponseYou've already chosen the best response.1
to figure out which is limiting you want to to take Grams of reactant >mols of reactant>moles of product with both... which ever can make the least amount of moles of product is your limiting reactant
 one year ago

Outkast3r09 Group TitleBest ResponseYou've already chosen the best response.1
or limiting aent
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
Fe2O3 M=55 m=250 n=4.5 Al M=26 m=150 n=5.7
 one year ago

Outkast3r09 Group TitleBest ResponseYou've already chosen the best response.1
alright and then there is 2 aluminum molecules per 2 iron
 one year ago

Outkast3r09 Group TitleBest ResponseYou've already chosen the best response.1
so you cna make 9.16 moles of iron with 9.16 moles of aluminum
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
wait 9.6 was error i took wrong mass Al n=5.7
 one year ago

Outkast3r09 Group TitleBest ResponseYou've already chosen the best response.1
o wait nvm 5.7 molecules of aluminum can make 5.7 molecules for iron
 one year ago

Outkast3r09 Group TitleBest ResponseYou've already chosen the best response.1
however per each iron oxide molecule you can make 2 iron oxide molecules
 one year ago

Outkast3r09 Group TitleBest ResponseYou've already chosen the best response.1
so multiply 4.5*2 =9 moles of iron.... since you can only make 5.7 moles with the aluminum , Al is your limiting reagent
 one year ago

Outkast3r09 Group TitleBest ResponseYou've already chosen the best response.1
now just change 5.7 moles of Fe to grams
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
m=5.7*55=322g
 one year ago

Outkast3r09 Group TitleBest ResponseYou've already chosen the best response.1
so that would be your answer
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
so cant we say there 2Al n=5.7 but 2 moles n=2(5.7)
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
answer not correct i think i made a mistake
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
the periodic table i am using says atomic weight =Al M=26g/mol is this the right thing to use as M
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
174.85 s the answer thanks
 one year ago
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