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It's the second step I am not getting.

THe picture I posted is near the final answer.

I see no other way to solve it.

Eww... More partial fractions?

But we only have 1 term divedby a polynomial . You have to use partial fractions.

Eww...

Thanks anyways.

Partial fractions do not help at all. You can't reduce this.

So it's actually possible to split this up? O_o .

yep

I got A,B,D = 0. C=1.

Is that right>

?**

i see that, too.
\[x=(1/2)(2x)=(1/2)(2x-2+2)=(1/2)(2x-2) + (1/2)(2)\]

So now I have:
\[\int\limits_{}^{}\frac{ 1 }{ (x^2-2x+5)^2 }dx\]

But we have a and b are 0 so the first term is entirely 0.

i realized that too, partial fraction doesn't work. check my previous post.

\[x=Ax^3-2Ax^2+Bx^2-2Bx+Cx+5B+D\]

Yeah okay hmm...

x-1=2tan(theta)
dx=2sec^2(theta) d(theta)

I get that which doesn't seem right...

I used u instead of y.

\[x-1=2\tan\theta\]
\[dx=2\sec ^2\theta d \theta\]

yes. our numerators agree.

@amistre64 , can you take over? i have to catch some sleep.

Thanks a lot :) .