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TedG
 2 years ago
i need a bit of clarification on why d/dx is always <0 to a given equation will type it out in the thread. anyone help me?
TedG
 2 years ago
i need a bit of clarification on why d/dx is always <0 to a given equation will type it out in the thread. anyone help me?

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TedG
 2 years ago
Best ResponseYou've already chosen the best response.1dx/dt= rx(1(x/k))h < 0 if h>rk/4

TedG
 2 years ago
Best ResponseYou've already chosen the best response.1i need to get my head around why this is

goformit100
 2 years ago
Best ResponseYou've already chosen the best response.0use the concept of maxima minin=ma...

TedG
 2 years ago
Best ResponseYou've already chosen the best response.1it what way? also how would this be derived?

TedG
 2 years ago
Best ResponseYou've already chosen the best response.1Because i'm answering a question on logistic growth with harvesting, have found steady states by setting rx(1(x/k))h=0 giving a quadratic.

TedG
 2 years ago
Best ResponseYou've already chosen the best response.1i need to find a critical harvesting point, which i have read is h_c=rk/4, and i need to be able to derive it.

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.0can you tell me your original function, and what each variable represents please?

TedG
 2 years ago
Best ResponseYou've already chosen the best response.1i will attach a print screen of the question i think that would explain what everything is.

TedG
 2 years ago
Best ResponseYou've already chosen the best response.1@TuringTest i have attached the question.

TedG
 2 years ago
Best ResponseYou've already chosen the best response.1so for one solving rx(1(x/k))h=0 gives a quadratic, which gives the steady states. what i want to know, is, i have read that the critical value is h_c=rk/4 but how?

TedG
 2 years ago
Best ResponseYou've already chosen the best response.1@TuringTest My assumption is maybe setting the discriminant of the quadratic to zero and rearranging. This does give h_c=rk/4. But i need to know that if this is correct why when h>h_c=rk/4 dx/dt is always 0.

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.0hm... still thinking
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