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natnatwebb

  • 3 years ago

Find the components of a vector u with magnitude 10 and direction angle theta=54 degrees.

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  1. muhammad9t5
    • 3 years ago
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    FOR X COMPONENT Ax=Acosx where x is angle for Y COMPONENT Ay=Asinx

  2. natnatwebb
    • 3 years ago
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    So there will be two equations. One to find the Y value and one for the X value.

  3. muhammad9t5
    • 3 years ago
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    Yes and these two values are called components.

  4. natnatwebb
    • 3 years ago
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    Okay, lemme throw those numbers into a calculator...

  5. natnatwebb
    • 3 years ago
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    they're both .5 which isn't anywhere near the right answer...is there another step?

  6. muhammad9t5
    • 3 years ago
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    whats the answer of x component?

  7. natnatwebb
    • 3 years ago
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    0.58778525229

  8. muhammad9t5
    • 3 years ago
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    and what you are getting?

  9. natnatwebb
    • 3 years ago
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    thats what I'm getting...did i miss a step?

  10. muhammad9t5
    • 3 years ago
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    Whats answer in your book?

  11. natnatwebb
    • 3 years ago
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    Oh sorry, \[u _{x}=5.9\]

  12. muhammad9t5
    • 3 years ago
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    whatss up?

  13. natnatwebb
    • 3 years ago
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    and \[u _{y}=\]

  14. natnatwebb
    • 3 years ago
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    8.1

  15. muhammad9t5
    • 3 years ago
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    math processing error?

  16. natnatwebb
    • 3 years ago
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    I'll go get a different calculator but i dont think so. Give me a second.

  17. natnatwebb
    • 3 years ago
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    I still get the same answer.

  18. muhammad9t5
    • 3 years ago
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    the answer i am getting for x component is 5.87 and for y component is 8.09

  19. natnatwebb
    • 3 years ago
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    I must be missing a step.

  20. muhammad9t5
    • 3 years ago
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    may be you don't multiply 10.

  21. muhammad9t5
    • 3 years ago
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    which is A=10

  22. natnatwebb
    • 3 years ago
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    yeah missed that part. :) lol well that fixes all the numbers nicely.

  23. natnatwebb
    • 3 years ago
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    :D sweet, glad it was such a simple fix. Thanks a lot for your help!

  24. muhammad9t5
    • 3 years ago
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    did you get answer?

  25. natnatwebb
    • 3 years ago
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    Yup.

  26. muhammad9t5
    • 3 years ago
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    You are welcome always!

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