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Jonask
 2 years ago
Best ResponseYou've already chosen the best response.1proof without using the rationalising by tan x and sec x \[\int\sec x=\ln (\tan x +\sec x)+c\]

Xavier
 2 years ago
Best ResponseYou've already chosen the best response.0Try partial fractions. secx=1/cosx=cosx/cos^2(x)=cosx/(1sin^2(x)) Then do a substitution u=sinx. Do partial fractions the show that the result is the same
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