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JonaskBest ResponseYou've already chosen the best response.1
proof without using the rationalising by tan x and sec x \[\int\sec x=\ln (\tan x +\sec x)+c\]
 one year ago

XavierBest ResponseYou've already chosen the best response.0
Try partial fractions. secx=1/cosx=cosx/cos^2(x)=cosx/(1sin^2(x)) Then do a substitution u=sinx. Do partial fractions the show that the result is the same
 one year ago
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