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overtonka

  • 3 years ago

expand each product (2x-7)(3x+8)

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  1. zenai
    • 3 years ago
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    Use the foil method - First Outer Inner Last \[(2x-7)(3x+8)\] 2x*3x first,\[6x^2\] 2x*8 second\[16x\] -7*3x next\[-21x\] -7*8 last equals -56 the full version : \[6x^2 + 16x - 21 x - 56\] combine like terms answer: \[6x^2 -5 x - 56\]

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