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louis413 Group TitleBest ResponseYou've already chosen the best response.1
pretend X^4 as x^2
 one year ago

Xavier Group TitleBest ResponseYou've already chosen the best response.0
Essentially what louis said. Make a subsitution u=x^2
 one year ago

louis413 Group TitleBest ResponseYou've already chosen the best response.1
so its like y^210y^2+9=0
 one year ago

louis413 Group TitleBest ResponseYou've already chosen the best response.1
then when u get some thing like (y21551515)(y611919) substitute x^2 back in
 one year ago

louis413 Group TitleBest ResponseYou've already chosen the best response.1
(BTW JUST made up the numbers.) i didnt solve it
 one year ago

sanguinepenguin95 Group TitleBest ResponseYou've already chosen the best response.0
i still dont undertsand..i can do the factoring for that equation but where does theother x^2 come in?
 one year ago

sanguinepenguin95 Group TitleBest ResponseYou've already chosen the best response.0
the factored form of that equation would be (y9)(y1) and then i do?
 one year ago

Comm.Dan Group TitleBest ResponseYou've already chosen the best response.0
x squared and x squared, 2x and 5x, 1 and 2, and 3 and 3
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.0
x^410x^2+9=0 let u = x^2 and if we square u: u^2 = x^4 replace x^4 with u^2 and x^2 with u u^2  10u +9 =0 solve for u once you get u, solve for x: remember u= x^2 so x= ± sqrt(u)
 one year ago

Comm.Dan Group TitleBest ResponseYou've already chosen the best response.0
I just factored this out, and not everything is able to be factorable @sanguinepenguin95
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.0
(y9)(y1) = 0 that means either (y9) is zero or (y1) is zero. you get 2 equations y9 =0 y1=0
 one year ago

louis413 Group TitleBest ResponseYou've already chosen the best response.1
yo u guys are making it too hard for him.... loook once u get (y9)(y1)... put X^2 into the "y"s and solve
 one year ago

Comm.Dan Group TitleBest ResponseYou've already chosen the best response.0
There are two monomials are not able to be factored @sanguinepenguin95
 one year ago

Comm.Dan Group TitleBest ResponseYou've already chosen the best response.0
It is not able to be factored any more, because there are two monomials that can't be factored any further @sanguinepenguin95
 one year ago

sanguinepenguin95 Group TitleBest ResponseYou've already chosen the best response.0
so it would be (x+3)(x3)(x+1)(x1)?
 one year ago

louis413 Group TitleBest ResponseYou've already chosen the best response.1
then to check plug the answers back in the orignial equations and whatever doesnt equals ... u cross off that answers. they're called like extraneous values i believe
 one year ago

sanguinepenguin95 Group TitleBest ResponseYou've already chosen the best response.0
Thankyou so much :)
 one year ago

louis413 Group TitleBest ResponseYou've already chosen the best response.1
x=3 3 1 1.... then plug them in the equation and whatever doesnt equals u cross them off
 one year ago

louis413 Group TitleBest ResponseYou've already chosen the best response.1
yeah no problem
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.0
I don't think I would do it quite that way. after you find y= 9 and y=1 you use x = ± sq rt(y) to get x= ± sqrt(9) and x= ± sqrt(1) in other words: x= +3, x= 3, x= +1 and x= 1
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.0
you have a 4th degree polynomial, so you should expect 4 (possibly repeated) roots.
 one year ago

louis413 Group TitleBest ResponseYou've already chosen the best response.1
... umm this is like alg 2 so id think theirs going to be 4th degree polynomial for this type of question..... maybe in calc or w/e
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Actually, this problem is very typical of an algebra II course.
 one year ago
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