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Xavier
 2 years ago
Best ResponseYou've already chosen the best response.0Essentially what louis said. Make a subsitution u=x^2

louis413
 2 years ago
Best ResponseYou've already chosen the best response.1so its like y^210y^2+9=0

louis413
 2 years ago
Best ResponseYou've already chosen the best response.1then when u get some thing like (y21551515)(y611919) substitute x^2 back in

louis413
 2 years ago
Best ResponseYou've already chosen the best response.1(BTW JUST made up the numbers.) i didnt solve it

sanguinepenguin95
 2 years ago
Best ResponseYou've already chosen the best response.0i still dont undertsand..i can do the factoring for that equation but where does theother x^2 come in?

sanguinepenguin95
 2 years ago
Best ResponseYou've already chosen the best response.0the factored form of that equation would be (y9)(y1) and then i do?

Comm.Dan
 2 years ago
Best ResponseYou've already chosen the best response.0x squared and x squared, 2x and 5x, 1 and 2, and 3 and 3

phi
 2 years ago
Best ResponseYou've already chosen the best response.0x^410x^2+9=0 let u = x^2 and if we square u: u^2 = x^4 replace x^4 with u^2 and x^2 with u u^2  10u +9 =0 solve for u once you get u, solve for x: remember u= x^2 so x= ± sqrt(u)

Comm.Dan
 2 years ago
Best ResponseYou've already chosen the best response.0I just factored this out, and not everything is able to be factorable @sanguinepenguin95

phi
 2 years ago
Best ResponseYou've already chosen the best response.0(y9)(y1) = 0 that means either (y9) is zero or (y1) is zero. you get 2 equations y9 =0 y1=0

louis413
 2 years ago
Best ResponseYou've already chosen the best response.1yo u guys are making it too hard for him.... loook once u get (y9)(y1)... put X^2 into the "y"s and solve

Comm.Dan
 2 years ago
Best ResponseYou've already chosen the best response.0There are two monomials are not able to be factored @sanguinepenguin95

Comm.Dan
 2 years ago
Best ResponseYou've already chosen the best response.0It is not able to be factored any more, because there are two monomials that can't be factored any further @sanguinepenguin95

sanguinepenguin95
 2 years ago
Best ResponseYou've already chosen the best response.0so it would be (x+3)(x3)(x+1)(x1)?

louis413
 2 years ago
Best ResponseYou've already chosen the best response.1then to check plug the answers back in the orignial equations and whatever doesnt equals ... u cross off that answers. they're called like extraneous values i believe

sanguinepenguin95
 2 years ago
Best ResponseYou've already chosen the best response.0Thankyou so much :)

louis413
 2 years ago
Best ResponseYou've already chosen the best response.1x=3 3 1 1.... then plug them in the equation and whatever doesnt equals u cross them off

phi
 2 years ago
Best ResponseYou've already chosen the best response.0I don't think I would do it quite that way. after you find y= 9 and y=1 you use x = ± sq rt(y) to get x= ± sqrt(9) and x= ± sqrt(1) in other words: x= +3, x= 3, x= +1 and x= 1

phi
 2 years ago
Best ResponseYou've already chosen the best response.0you have a 4th degree polynomial, so you should expect 4 (possibly repeated) roots.

louis413
 2 years ago
Best ResponseYou've already chosen the best response.1... umm this is like alg 2 so id think theirs going to be 4th degree polynomial for this type of question..... maybe in calc or w/e

calmat01
 2 years ago
Best ResponseYou've already chosen the best response.0Actually, this problem is very typical of an algebra II course.
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