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wannabegurl
 3 years ago
Can somebody explian to me dependent and independent probability
wannabegurl
 3 years ago
Can somebody explian to me dependent and independent probability

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Independent events in probability is when two events do not affect each others outcome. For example if you flip a coin twice, the event that the first flip is heads is independent of the event that the second flip is heads.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0However if you have an event where both flips are heads, then the event that the first flip is heads affects the outcome of this event. You know it is more likely to happen then before the first flip. Thus the events are dependent on each other.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The significance of this is that if two events are independent, then the chance of then both happening is \[ \Pr(AB) = \Pr(A) \times \Pr(B) \]

wannabegurl
 3 years ago
Best ResponseYou've already chosen the best response.0@wio so if I had a bag with a square ,circle,two triangles what. Would be P(T,circle) ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What do you mean P (T, circle)? what are the events?

wannabegurl
 3 years ago
Best ResponseYou've already chosen the best response.0@wio sorry and a penny so tails would be T in P(T,circle)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What is the even that is happening?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0a penny so tails is not an event.

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.0it sounds like P(T,circle) = "probability of flipping a penny to land on tails AND picking a circle out of the bag"

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@wannabegurl is he right?

wannabegurl
 3 years ago
Best ResponseYou've already chosen the best response.0Yes @wio he is right thanks @jim_thompson5910

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Then use the formula I wrote, since the flip is independent of the draw. \[ \Pr(T,\circ)=\Pr(T)\times \Pr(\circ) \]

wannabegurl
 3 years ago
Best ResponseYou've already chosen the best response.0Ok @wio if you say soo

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.0You could draw out a table to help you find the probability dw:1361673237553:dw

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.0Each cell would get the respective header from each row and column for example, this cell marked with an X dw:1361673403499:dw would have "H, Square" and this is the outcome where you flip a heads and pull out a square so you would enter that into the upper right cell to get dw:1361673459247:dw