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wannabegurl
Group Title
Can somebody explian to me dependent and independent probability
 one year ago
 one year ago
wannabegurl Group Title
Can somebody explian to me dependent and independent probability
 one year ago
 one year ago

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wio Group TitleBest ResponseYou've already chosen the best response.3
Independent events in probability is when two events do not affect each others outcome. For example if you flip a coin twice, the event that the first flip is heads is independent of the event that the second flip is heads.
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.3
However if you have an event where both flips are heads, then the event that the first flip is heads affects the outcome of this event. You know it is more likely to happen then before the first flip. Thus the events are dependent on each other.
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.3
The significance of this is that if two events are independent, then the chance of then both happening is \[ \Pr(AB) = \Pr(A) \times \Pr(B) \]
 one year ago

wannabegurl Group TitleBest ResponseYou've already chosen the best response.0
@wio so if I had a bag with a square ,circle,two triangles what. Would be P(T,circle) ?
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.3
What do you mean P (T, circle)? what are the events?
 one year ago

wannabegurl Group TitleBest ResponseYou've already chosen the best response.0
@wio sorry and a penny so tails would be T in P(T,circle)
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.3
What is the even that is happening?
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.3
a penny so tails is not an event.
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
it sounds like P(T,circle) = "probability of flipping a penny to land on tails AND picking a circle out of the bag"
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.3
@wannabegurl is he right?
 one year ago

wannabegurl Group TitleBest ResponseYou've already chosen the best response.0
Yes @wio he is right thanks @jim_thompson5910
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.3
Then use the formula I wrote, since the flip is independent of the draw. \[ \Pr(T,\circ)=\Pr(T)\times \Pr(\circ) \]
 one year ago

wannabegurl Group TitleBest ResponseYou've already chosen the best response.0
Ok @wio if you say soo
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
You could draw out a table to help you find the probability dw:1361673237553:dw
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
Each cell would get the respective header from each row and column for example, this cell marked with an X dw:1361673403499:dw would have "H, Square" and this is the outcome where you flip a heads and pull out a square so you would enter that into the upper right cell to get dw:1361673459247:dw
 one year ago