## mitchelsewbaran Group Title Verify the identity. cos 4u= cos^2(2u)- sin^2 (2u) one year ago one year ago

1. mathslover Group Title

Put 'u' as any angle ... let it be $$\large{\frac{\pi}{2}}$$ .

2. mathslover Group Title

What do you get now as : $$\large{\cos(4(\frac{\pi}{2}))}$$ = ?

3. mathslover Group Title

Can you tell me @mitchelsewbaran

4. .Sam. Group Title

I would use cos(4u) cos(2u+2u) Then by identity: cos(A+B)=cosAcosB-sinAsinB cos(2u)cos(2u)-sin(2u)sin(2u) cos^2(2u)-sin^2(2u)

5. mathslover Group Title

Is that verification or proof @.Sam. I think we have to verify and not to prove

6. mitchelsewbaran Group Title

cos(4(π 2 )) = 1

7. .Sam. Group Title

If they both equal then that's verifying too

8. mathslover Group Title

right now solve this : $\large{\cos^2(2(\frac{\pi}{2}))- \sin^2(2(\frac{\pi}{2}))}$

9. mitchelsewbaran Group Title

hold on

10. mathslover Group Title

11. mitchelsewbaran Group Title

1?

12. mathslover Group Title

yes can you tell me how you got that ?

13. mitchelsewbaran Group Title

I replaced that whole equation with cos(2pi). Taking the cosine of 2pi, I got 1

14. mathslover Group Title

o.O a small mistake @mitchelsewbaran : see here: $\large{\cos^2(2(\frac{\pi}{2})) - \sin^2(2(\frac{\pi}{2}))}$ $\large{\cos^2(\pi) - \sin^2(\pi)}$ $\large{1-0= 1}$

15. mitchelsewbaran Group Title

16. mathslover Group Title

No problem I just corrected you and I hope that you will not repeat that again. Best of luck :)

17. mitchelsewbaran Group Title

I have only 2 more that I need to verify. I was wondering if you can help?

18. tkhunny Group Title

You cannot substitute a single value (or any finite number of values) to PROVE this. If you find one that doesn't work, that would be sufficient to DISprove it.

19. mathslover Group Title

Did you try yourself first?

20. mitchelsewbaran Group Title

can u help me verify these last 2?

21. mathslover Group Title

there is not fight @mitchelsewbaran . sorry if you felt bad. @tkhunny the question is to verify .. and hence we have to put a value and verify it

22. mitchelsewbaran Group Title

@mathslover ok :)

23. mitchelsewbaran Group Title

no I didn't feel bad @mathslover

24. tkhunny Group Title

@mathslover Demonstrating one or two values is just not what it is asking. It must be verified for ALL values. Since you cannot enter infinitely many values, there must be other methods employed. Demonstrating $$x = \pi$$ says nothing of $$x = \sqrt{2}$$

25. mathslover Group Title

Ok @mitchelsewbaran post the one question of that two there in "ask a question forum" and surely I will help you but the second one will be solved by you and I will check it... if you get any problem in any concept you can ask me.

26. mitchelsewbaran Group Title

ok :)

27. mitchelsewbaran Group Title

@mathlover u're awesome, bro :)

28. mathslover Group Title

:)

29. mitchelsewbaran Group Title

;)

30. mathslover Group Title

well I think @tkhunny has a point but still it is not given to verify for all values... it is just to verify.. but if we still go on for a proving method .. then it's surely not verifying

31. tkhunny Group Title

No, this is just not the case. "Verify the Identity" has meant to provide a general proof for all possible values in the entire Domain - at least since 1972. I am familiar with no reference in any mathematical text that has ever meant anything else. If only a few values were to be sufficient, the problem statement would say something like this, "Verify a few values and formulate a conjecture on whether or not this statement is generally true." "Verify the Identity" means ALL of them - leaving nothing out.