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ihavemathquestions
Group Title
Determine whether y varies directly with x. If so, find the constant of variation k.
3y = –7x – 18
 one year ago
 one year ago
ihavemathquestions Group Title
Determine whether y varies directly with x. If so, find the constant of variation k. 3y = –7x – 18
 one year ago
 one year ago

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ihavemathquestions Group TitleBest ResponseYou've already chosen the best response.2
 one year ago

ihavemathquestions Group TitleBest ResponseYou've already chosen the best response.2
@agent0smith
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
For the constant of variation, we need it to look like y = kx. Let's divide both sides of 3y = –7x – 18 by 3, to get \[y = \frac{7 }{ 3 }x –\frac{ 18 }{3 }\] Try comparing \[y= kx \]to\[y = \frac{7 }{ 3 }x –\frac{ 18 }{3 }\]
 one year ago

ihavemathquestions Group TitleBest ResponseYou've already chosen the best response.2
so is the answer B?
 one year ago

ihavemathquestions Group TitleBest ResponseYou've already chosen the best response.2
@agent0smith
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
But notice that we have\[ y = \frac{7 }{ 3 }x –\frac{ 18 }{3 } \] Does it look like y=kx? or y=kx minus 18/3?
 one year ago

ihavemathquestions Group TitleBest ResponseYou've already chosen the best response.2
no they don't so its D
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
For constant of variation, you only want y = kx, not y = kx plus or minus some number.
 one year ago

ihavemathquestions Group TitleBest ResponseYou've already chosen the best response.2
so there is no constant of variation its no
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
Correct :) *If* it was just \[y = \frac{7 }{ 3 }x\] then it would be in the form y = kx.
 one year ago

ihavemathquestions Group TitleBest ResponseYou've already chosen the best response.2
thanks baby xo
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
haha no prob :)
 one year ago
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