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Hi! I'm Claudine Veluya a 2nd year college student.
could someone have an additional information about parabola? thank you.
 one year ago
 one year ago
Hi! I'm Claudine Veluya a 2nd year college student. could someone have an additional information about parabola? thank you.
 one year ago
 one year ago

This Question is Open

UnkleRhaukusBest ResponseYou've already chosen the best response.0
hello, what information about parabola do you already have?
 one year ago

claudineVeluyaBest ResponseYou've already chosen the best response.1
I'm i right that Parabola is a set of all points equidistant from a line and a fixed point not on the line, the line is called the directrix, and the point is called the focus. The point on the parabola halfway between the focus and the directrix is the vertex. The line containing the focus and the vertex is the axis. A parabola is symmetric with respect to its axis.
 one year ago

sirm3dBest ResponseYou've already chosen the best response.0
also, the segment joining two points of the parabola, parallel to the directrix and through the focus is the latus rectum of the parabola.
 one year ago

claudineVeluyaBest ResponseYou've already chosen the best response.1
the Latus rectum of the parabola is use if they have the given of vertex. I'm i right. sirm3d.
 one year ago

harsimran_hs4Best ResponseYou've already chosen the best response.0
well what i suggest is that you should refer some text for parabola as it will give you better understanding
 one year ago

claudineVeluyaBest ResponseYou've already chosen the best response.1
oh its that an example of Parabola? unkleRhaukus
 one year ago

agent0smithBest ResponseYou've already chosen the best response.2
^ yep, any object thrown up into the air (other than straight up) follows a parabolic path due to gravity.
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
you can make a parabola by holding a string between two points
 one year ago

agent0smithBest ResponseYou've already chosen the best response.2
@UnkleRhaukus won't that make a catenary curve?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
dw:1361698911624:dw
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
ok @agent0smith, your right , the hanging string is a catenary curve which is not quite the same as a parabola, but they look kinda similar
 one year ago

agent0smithBest ResponseYou've already chosen the best response.2
^ yep and you can model them with a parabola pretty closely.
 one year ago

claudineVeluyaBest ResponseYou've already chosen the best response.1
i"m right that is an example of Property of Parabolas because The tangent line at a point P on a parabola makes equal with the line through P parallel to axis of symmetry and the line through P and the focus. let P dw:1361757582217:dw
 one year ago

claudineVeluyaBest ResponseYou've already chosen the best response.1
hi! Do you think that it is way to derive the Parabola? DERIVATION OF PARABOLA A parabola coinciding was xaxis Its vertex at the origin Its focus at the (p,o) And its directix is x=p Where p is called distance Then we choose any point P(x,y) By the definition of parabola FP=SP (√((xp)^2+ y^2 ))^2= (x+p)^2 (x+p)^2+y^2= (x+p)^2 x^2 2px+y^2= x^2+ 2px+ p^2 y^2= x^2+ 2px+p^2 x^2+ 2px p^2 〖 y〗^2=4px DERIVATION OF PARABOLA A parabola coinciding was xaxis Its vertex at the origin Its focus at the (p,o) And its directix is x=p Where p is called distance Then we choose any point P(x,y) By the definition of parabola FP=SP (√((xp)^2+ y^2 ))^2= (x+p)^2 (x+p)^2+y^2= (x+p)^2 x^2 2px+y^2= x^2+ 2px+ p^2 y^2= x^2+ 2px+p^2 x^2+ 2px p^2 〖 y〗^2=4px can you give me other way of derivation of Parabola?
 one year ago
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