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ksaimouli

limit

  • one year ago
  • one year ago

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  1. ksaimouli
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    \[\lim_{x \rightarrow {-\infty}}\frac{ 2x-1 }{ 1+2x }\]

    • one year ago
  2. ksaimouli
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    when i divide by x i get |dw:1361724743582:dw|

    • one year ago
  3. ksaimouli
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    and this leads me to 1 but the answer was -1

    • one year ago
  4. ZeHanz
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    OK, now what is lim x to inf of 1/x?

    • one year ago
  5. ksaimouli
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    plz help with this

    • one year ago
  6. ksaimouli
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    0

    • one year ago
  7. ksaimouli
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    |dw:1361724809521:dw|

    • one year ago
  8. ksaimouli
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    =1

    • one year ago
  9. ZeHanz
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    So you get (2-0)/(0+2)=2/2=1

    • one year ago
  10. ksaimouli
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    as this goes to - infin it is -1

    • one year ago
  11. ksaimouli
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    i mean i got -1 bu the book says it is 1

    • one year ago
  12. ZeHanz
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    No, it is not. It is always 1

    • one year ago
  13. ksaimouli
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    why

    • one year ago
  14. ksaimouli
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    as it goes to - infinity to should go to -1 right

    • one year ago
  15. ZeHanz
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    Because you end up with (2x)/(2x) = 1

    • one year ago
  16. ksaimouli
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    okay i got thx so no matter what after dividing we get the answer and i should not check the limit right

    • one year ago
  17. ZeHanz
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    Just try a very big neg number, say x = -100000. Then the quotiens is: -200001/-199999, which is about 1

    • one year ago
  18. ZeHanz
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    So you can even check the limit.

    • one year ago
  19. phi
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    I am guessing a typo in the question or the answer.

    • one year ago
  20. ZeHanz
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    @phi: me too

    • one year ago
  21. ZeHanz
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    Remember: sometimes, even books are wrong ;)

    • one year ago
  22. phi
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    especially math books. Proof readers miss all kinds of mistakes.

    • one year ago
  23. ksaimouli
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    the answer is 1

    • one year ago
  24. ZeHanz
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    Yes, @ksaimouli , you were right all the time!

    • one year ago
  25. ksaimouli
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    thx

    • one year ago
  26. ZeHanz
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    YW!

    • one year ago
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