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ksaimouli
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\[\lim_{x \rightarrow {\infty}}\frac{ 2x1 }{ 1+2x }\]

ksaimouli
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when i divide by x i get dw:1361724743582:dw

ksaimouli
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and this leads me to 1 but the answer was 1

ZeHanz
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OK, now what is lim x to inf of 1/x?

ksaimouli
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plz help with this

ksaimouli
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0

ksaimouli
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dw:1361724809521:dw

ksaimouli
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=1

ZeHanz
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So you get (20)/(0+2)=2/2=1

ksaimouli
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as this goes to  infin it is 1

ksaimouli
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i mean i got 1 bu the book says it is 1

ZeHanz
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No, it is not. It is always 1

ksaimouli
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why

ksaimouli
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as it goes to  infinity to should go to 1 right

ZeHanz
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Because you end up with (2x)/(2x) = 1

ksaimouli
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okay i got thx so no matter what after dividing we get the answer and i should not check the limit right

ZeHanz
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Just try a very big neg number, say x = 100000.
Then the quotiens is: 200001/199999, which is about 1

ZeHanz
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So you can even check the limit.

phi
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I am guessing a typo in the question or the answer.

ZeHanz
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@phi: me too

ZeHanz
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Remember: sometimes, even books are wrong ;)

phi
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especially math books. Proof readers miss all kinds of mistakes.

ksaimouli
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the answer is 1

ZeHanz
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Yes, @ksaimouli , you were right all the time!

ksaimouli
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thx

ZeHanz
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YW!