Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

S

  • 3 years ago

Starting with 1.20 g A, what is the mass of A remaining undercomposed after 1.00h? ( t1/2= 16 min)

  • This Question is Closed
  1. aaronq
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you can simplify this formula: \[A=A _{0}e ^{-kt}\] to this: \[A=A _{0}(\frac{ 1 }{ 2 })^{\frac{ t }{ t _{1/2} }}\] A=amount after time elapsed Ao=initial amount t= time t1/2= half life

  2. JFraser
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    you can also approximate 16min as 1/4 of 1 hour, so 4 half-lives will pass over that time span. 1/16 of the 1.20g will remain after 1 hour (more or less)

  3. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy