Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

inverse tan[tan(6pi/7)] i need an exact answer using pi as needed. can someone explain to me how to solve this?

Trigonometry
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
Sorry I mean \[\huge \arctan\left( \tan (6\pi/7) \right) \] or \[\huge \tan^{-1}\left( \tan (6\pi/7) \right) \]
\[\tan^{-1} [\tan (6\pi/7)]\]
What do you know about inverse functions? (they're super important to answering this question).

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

um i know how to put them in my calculator and that they have restrictions this particular one the answer must be in either quadrant 1 or 4...
The key is that an inverse function "undoes" a function. arctan ( tan ( stuff ) ) = stuff and tan ( arctan ( stuff ) ) = stuff (assuming domains and ranges are valid) also \(\large \arctan(x) = \tan^{-1}(x) \) it's just notation. They mean the same exact thing.
so would the answer just be 6pi/7 since the inverse tan would undo tan?
  • phi
yes
thanks (: does that apply to any function that has the inverse of the same function on the outside?
6pi/7 or -pi/7, they are the same thing. And yes, inverse function ( function ( stuff ) ) = stuff function ( inverse function ( stuff ) ) = stuff Inverse functions and functions "undo" each other. That's glossing over a lot of details, but that's the big idea. :)
  • phi
yes, and vice versa.
what if it was something like \[\tan [\tan^{-1}(\pi/10)] \]
the simplified version of 6pi/7 would be just pi/7 ?
  • phi
yes, pi/10 you can check with your calculator tan^-1 (pi/10) you are treating pi/10 as a number not as an angle.
  • phi
the simplified version of 6pi/7 would be just pi/7 ? I would not say "simplified" If you mean Is pi/7 the "reference angle" of 6pi/7, that is true
the problem says simplify and use pi as needed..
  • phi
In that case, the answer is 6 pi/7 (about 154.29ยบ)
  • phi
unless they want the answer between -pi/2 and pi/2 in which case they want -pi/7 (see math teacher's post)
ok thank you sooo much ! i have test on this tomorrow and i had no clue how to do it! you are a lifesaver!

Not the answer you are looking for?

Search for more explanations.

Ask your own question