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Sda370

  • 3 years ago

Cot^2 x + cot x = 0

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  1. Ephilo
    • 3 years ago
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    what is the question asking?

  2. Sda370
    • 3 years ago
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    No written question, just have to solve for that

  3. anonymous
    • 3 years ago
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    \[\cot(x)\left(\cot(x)+1\right)=0\] \[\iff \cot(x)=0\] or \[\cot(x)=-1\]

  4. Sda370
    • 3 years ago
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    Got it, thank you!

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