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hary
Group Title
du(x)/dx tan(x)u(x)=2sinx
find u(x)
inhomogeneous differential equation
 one year ago
 one year ago
hary Group Title
du(x)/dx tan(x)u(x)=2sinx find u(x) inhomogeneous differential equation
 one year ago
 one year ago

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SithsAndGiggles Group TitleBest ResponseYou've already chosen the best response.0
\[u'(\tan x)u=2\sin x\\ (\cos x)u'(\sin x)u=2\sin x\cos x\] What can you say about the LHS?
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.2
I saw you were stuck on this one earlier hary, what was the book answer again?
 one year ago

hary Group TitleBest ResponseYou've already chosen the best response.0
u=cosx +C/cosx this was the book answer
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.2
Ah ok good. You must've made a small mistake near the end then. Because your integrating factor looked good.
 one year ago

hary Group TitleBest ResponseYou've already chosen the best response.0
hmm im guessing the same too..but couldnt figure out where
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.2
\[\large u \cos x=2 \int\limits \sin x \cos x dx\] \[\large m=\cos x\]\[\large dm=\sin x dx\] Applying this substitution gives us,\[\large u \cos x=2 \int\limits m dm\] \[\large u \cos x=m^2+C\] \[\large u \cos x=\cos^2x+C\]
 one year ago

hary Group TitleBest ResponseYou've already chosen the best response.0
owh god thats brilliant...did a blunder at my RHS integration
 one year ago

myko Group TitleBest ResponseYou've already chosen the best response.0
lol, what a mistake. Time for me to go to sleep I think
 one year ago

hary Group TitleBest ResponseYou've already chosen the best response.0
@zepdix thanks alot!!!! was cracking my head on this for quite long...pheww thats a relief... thankx again...
 one year ago

hary Group TitleBest ResponseYou've already chosen the best response.0
@myko thankx to you too...been a great help
 one year ago
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