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SithsAndGiggles
 one year ago
Best ResponseYou've already chosen the best response.0\[u'(\tan x)u=2\sin x\\ (\cos x)u'(\sin x)u=2\sin x\cos x\] What can you say about the LHS?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2I saw you were stuck on this one earlier hary, what was the book answer again?

hary
 one year ago
Best ResponseYou've already chosen the best response.0u=cosx +C/cosx this was the book answer

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Ah ok good. You must've made a small mistake near the end then. Because your integrating factor looked good.

hary
 one year ago
Best ResponseYou've already chosen the best response.0hmm im guessing the same too..but couldnt figure out where

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2\[\large u \cos x=2 \int\limits \sin x \cos x dx\] \[\large m=\cos x\]\[\large dm=\sin x dx\] Applying this substitution gives us,\[\large u \cos x=2 \int\limits m dm\] \[\large u \cos x=m^2+C\] \[\large u \cos x=\cos^2x+C\]

hary
 one year ago
Best ResponseYou've already chosen the best response.0owh god thats brilliant...did a blunder at my RHS integration

myko
 one year ago
Best ResponseYou've already chosen the best response.0lol, what a mistake. Time for me to go to sleep I think

hary
 one year ago
Best ResponseYou've already chosen the best response.0@zepdix thanks alot!!!! was cracking my head on this for quite long...pheww thats a relief... thankx again...

hary
 one year ago
Best ResponseYou've already chosen the best response.0@myko thankx to you too...been a great help
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