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SithsAndGiggles
 2 years ago
Best ResponseYou've already chosen the best response.0\[u'(\tan x)u=2\sin x\\ (\cos x)u'(\sin x)u=2\sin x\cos x\] What can you say about the LHS?

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.2I saw you were stuck on this one earlier hary, what was the book answer again?

hary
 2 years ago
Best ResponseYou've already chosen the best response.0u=cosx +C/cosx this was the book answer

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.2Ah ok good. You must've made a small mistake near the end then. Because your integrating factor looked good.

hary
 2 years ago
Best ResponseYou've already chosen the best response.0hmm im guessing the same too..but couldnt figure out where

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.2\[\large u \cos x=2 \int\limits \sin x \cos x dx\] \[\large m=\cos x\]\[\large dm=\sin x dx\] Applying this substitution gives us,\[\large u \cos x=2 \int\limits m dm\] \[\large u \cos x=m^2+C\] \[\large u \cos x=\cos^2x+C\]

hary
 2 years ago
Best ResponseYou've already chosen the best response.0owh god thats brilliant...did a blunder at my RHS integration

myko
 2 years ago
Best ResponseYou've already chosen the best response.0lol, what a mistake. Time for me to go to sleep I think

hary
 2 years ago
Best ResponseYou've already chosen the best response.0@zepdix thanks alot!!!! was cracking my head on this for quite long...pheww thats a relief... thankx again...

hary
 2 years ago
Best ResponseYou've already chosen the best response.0@myko thankx to you too...been a great help
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