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Ephilo

  • 3 years ago

HELP PLEASE)..Estimate the area of the given function, f(x) = x2 + 1 using 4 inscribed rectangles on the interval [2, 4].

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  1. Ephilo
    • 3 years ago
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    @mathsmind this one first tho

  2. mathsmind
    • 3 years ago
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    what i understand is that we have to integrate between 2 and 4

  3. mathsmind
    • 3 years ago
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    i am having some problems it says [Math Processing Error]

  4. mathsmind
    • 3 years ago
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    \[int_{2}^{4} x^2 dx\]

  5. mathsmind
    • 3 years ago
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    or is it about drawing estimating the area of the parabula using blocks of squares...

  6. Ephilo
    • 3 years ago
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    i dont know but this one is too hard :( its worth 7.0 pts im so confused, i feel like crying

  7. mathsmind
    • 3 years ago
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    \[int_{2}^{4} x^2 dx \]

  8. Ephilo
    • 3 years ago
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    this work is getting to hard for me

  9. mathsmind
    • 3 years ago
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    well you have to suffere the pain of knowledge and hardship for a better future, we all went through hard times ...

  10. mathsmind
    • 3 years ago
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    you should fight back and not let the questions beat you ...

  11. mathsmind
    • 3 years ago
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    i think this question is saying estimate the area using rectangles, on a proper sheet

  12. mathsmind
    • 3 years ago
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    so first of all we need to divid the interval

  13. mathsmind
    • 3 years ago
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    what i mean by that is to divide the interval into 4 sub inscribed intervals

  14. mathsmind
    • 3 years ago
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    let it be 2, 2.5, 3, 3.5 and 4 because they 2 and 4 are included in the interval using square brackets notation...

  15. Ephilo
    • 3 years ago
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    okay,i'm working on it

  16. mathsmind
    • 3 years ago
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    are you with me, this is the logic of the question from my understanding

  17. mathsmind
    • 3 years ago
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    I am sorry that the equation editor is not functioning propely for me, probably due to browser issue, or technical problem with open study...

  18. mathsmind
    • 3 years ago
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    A = 0.5[f(2)+f(2.5)+f(3)+f(3.5)+f(4)

  19. Ephilo
    • 3 years ago
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    i'm looking,i'm here trying to understand

  20. mathsmind
    • 3 years ago
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    so what is f(2)=?

  21. mathsmind
    • 3 years ago
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    now before that the reason why i divided the intervals by a step of 0.5 is due to the fact that dx = (4-2)/4=0.5, hence 2, 2.5...etc

  22. mathsmind
    • 3 years ago
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    let me help you on the first one f(2) = (2)^2+1=4+1=5

  23. mathsmind
    • 3 years ago
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    what is f(3)=?

  24. mathsmind
    • 3 years ago
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    what is f(2.5)=?

  25. mathsmind
    • 3 years ago
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    what is f(3.5)=?

  26. mathsmind
    • 3 years ago
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    and finally what is f(4)=?

  27. Ephilo
    • 3 years ago
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    give me a coplue mins as i work on finish another problem

  28. Ephilo
    • 3 years ago
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    i don't understand how you got the f(2)= part

  29. mathsmind
    • 3 years ago
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    ok i will solve it i am replying to 287489327498732987498237 posts at the same time ... hehehe

  30. Ephilo
    • 3 years ago
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    lol okay, i can't keep hogging you,ill be working on others as i wait.

  31. mathsmind
    • 3 years ago
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    now young lady, let's see what your problem is...

  32. mathsmind
    • 3 years ago
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    step one: dx = (4-2)/4 = 1/2=0.5

  33. mathsmind
    • 3 years ago
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    step two divide the interval [2, 4] into [2, 2.5, 3, 3.5, 4]

  34. mathsmind
    • 3 years ago
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    step three find : A = 0.5[f(2)+f(2.5)+f(3)+f(3.5)+f(4)]

  35. mathsmind
    • 3 years ago
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    f(2) =(2)^2+1=5, f(2.5)=(2.5)^2+1= 7.25. f(3)=(3)^2+1=10, f(3.5)=(3.5)^2+1=13.25, and f(4) = (4)^2+1=17

  36. mathsmind
    • 3 years ago
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    : A = 0.5[5+7.25+10+13.25+17]=? use the calculator

  37. mathsmind
    • 3 years ago
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    @Ephilo are you there...?

  38. Ephilo
    • 3 years ago
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    yes im writing it on paper

  39. mathsmind
    • 3 years ago
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    you need to understand what we did, it is a numerical integration method ....

  40. Ephilo
    • 3 years ago
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    i understand

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