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modphysnoob
 2 years ago
see below
modphysnoob
 2 years ago
see below

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modphysnoob
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1361760894694:dw

modphysnoob
 2 years ago
Best ResponseYou've already chosen the best response.0so how would band diagram look like @Jemurray3

Jemurray3
 2 years ago
Best ResponseYou've already chosen the best response.1Consider what kind of potential would yield such an electric field diagram, then basically tack it on to the band diagram.

modphysnoob
 2 years ago
Best ResponseYou've already chosen the best response.0that would be integral of the that?

modphysnoob
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1361762119933:dw

Jemurray3
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1361762223289:dw

modphysnoob
 2 years ago
Best ResponseYou've already chosen the best response.0ok, got it , and this is v vs x graph how do we go to band diagram?

Jemurray3
 2 years ago
Best ResponseYou've already chosen the best response.1In the absence of a field, the band diagram may look like this: dw:1361762537191:dw

modphysnoob
 2 years ago
Best ResponseYou've already chosen the best response.0so how does electric field alter it

Jemurray3
 2 years ago
Best ResponseYou've already chosen the best response.1If you add an constant electric field pointing to the right, that means that the energy of a positively charged particle would be higher on the left than on the right so the bands would shift: dw:1361762863943:dw

modphysnoob
 2 years ago
Best ResponseYou've already chosen the best response.0that's our middle part

Jemurray3
 2 years ago
Best ResponseYou've already chosen the best response.1Yep. The rest is similar.

modphysnoob
 2 years ago
Best ResponseYou've already chosen the best response.0thanks man , you've been a great help
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