Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

sharon_penn

  • 3 years ago

help please

  • This Question is Closed
  1. sharon_penn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1 Attachment
  2. sharon_penn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1 Attachment
  3. sharon_penn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1 Attachment
  4. sharon_penn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1 Attachment
  5. sharon_penn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1 Attachment
  6. sharon_penn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1 Attachment
  7. Directrix
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    The theorem I think we need is this one: Theorem: If an altitude is drawn to the hypotenuse of a right triangle, either leg of the triangle is the geometric mean between the length of the hypotenuse and the segment of the hypotenuse adjacent to that leg.

  8. sharon_penn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    go on

  9. Directrix
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Go ahead. I was just writing up a drawing for this problem.

  10. Directrix
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

  11. Directrix
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @sharon_penn I'm waiting for you to say something about solving the equations on the attachment.

  12. Directrix
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I know how to do this and will help if you will just tell me what your thinking is on the problem.

  13. sharon_penn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    My thought was that the sides would equal so I thought that the answer x=2sqrt3 y=4 was correct

  14. sharon_penn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    am i right?

  15. Directrix
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I'll work the equation here. y/12 = 28/y y = 4*sqrt(21)

  16. sharon_penn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    awesome

  17. Directrix
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    16/x = x/28 x = 8*sqrt(7)

  18. Directrix
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Is that what you got?

  19. sharon_penn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no but I see how you got it :)

  20. Directrix
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Okay. Learn those Geometry theorems. :)

  21. sharon_penn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ty

  22. Directrix
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Glad to help.

  23. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy