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Quadratic Equation: (x-4)(x-6)=2

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You're supposed to find x, am I right? :)
haha i dont know :) i think yes?
Well, perform the FOIL method on (x-4)(x-6). You get...?

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Other answers:

what will you do with 2?
Patience :) FOIL method on the left-hand-side you get x² - 10x + 24 right?
so... x² - 10x + 24 = 2 Now you can more clearly see what to do with the 2, am I right? ;)
you cant find x
then what is it?
use FOIL
know what that is?
yes. i got x^2-10x+24=2
then whats next?
Now add -2 to both sides
Well, transpose 2, from the right side to the left... x² - 10x + 22 = 0
oohh i get it. then what?
Use the quadratic formula. Everything falls into place.
i really cant. please help me :(
Given your equation in the form ax² + bx + c = 0 Your x values are given by \[\huge \frac{-b \ \pm \ \sqrt{b^2-4ac}}{2a}\]
Plug in and solve.
what is my a ? my b is 10? my c is 24 ?
i mean my c is 20?
your b is -10 not just 10 a is 1, as there is no coefficient.
c is 22, not 24. Look again.
oh okay :) then whats next?
ill just solve it?
i think we're going to do a standard equation not quadratic equation?!
standard form rather

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