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alfers101

  • 3 years ago

Quadratic Equation: (x-4)(x-6)=2

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  1. terenzreignz
    • 3 years ago
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    You're supposed to find x, am I right? :)

  2. alfers101
    • 3 years ago
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    haha i dont know :) i think yes?

  3. terenzreignz
    • 3 years ago
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    Well, perform the FOIL method on (x-4)(x-6). You get...?

  4. alfers101
    • 3 years ago
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    what will you do with 2?

  5. terenzreignz
    • 3 years ago
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    Patience :) FOIL method on the left-hand-side you get x² - 10x + 24 right?

  6. alfers101
    • 3 years ago
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    yes

  7. terenzreignz
    • 3 years ago
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    so... x² - 10x + 24 = 2 Now you can more clearly see what to do with the 2, am I right? ;)

  8. GaLm
    • 3 years ago
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    .....

  9. GaLm
    • 3 years ago
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    you cant find x

  10. alfers101
    • 3 years ago
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    then what is it?

  11. GaLm
    • 3 years ago
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    use FOIL

  12. GaLm
    • 3 years ago
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    know what that is?

  13. alfers101
    • 3 years ago
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    yes. i got x^2-10x+24=2

  14. alfers101
    • 3 years ago
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    then whats next?

  15. terenzreignz
    • 3 years ago
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    Now add -2 to both sides

  16. alfers101
    • 3 years ago
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    what?

  17. terenzreignz
    • 3 years ago
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    Well, transpose 2, from the right side to the left... x² - 10x + 22 = 0

  18. alfers101
    • 3 years ago
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    oohh i get it. then what?

  19. terenzreignz
    • 3 years ago
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    Use the quadratic formula. Everything falls into place.

  20. alfers101
    • 3 years ago
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    i really cant. please help me :(

  21. terenzreignz
    • 3 years ago
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    Given your equation in the form ax² + bx + c = 0 Your x values are given by \[\huge \frac{-b \ \pm \ \sqrt{b^2-4ac}}{2a}\]

  22. terenzreignz
    • 3 years ago
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    Plug in and solve.

  23. alfers101
    • 3 years ago
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    what is my a ? my b is 10? my c is 24 ?

  24. alfers101
    • 3 years ago
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    i mean my c is 20?

  25. terenzreignz
    • 3 years ago
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    your b is -10 not just 10 a is 1, as there is no coefficient.

  26. terenzreignz
    • 3 years ago
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    c is 22, not 24. Look again.

  27. alfers101
    • 3 years ago
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    oh okay :) then whats next?

  28. alfers101
    • 3 years ago
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    ill just solve it?

  29. terenzreignz
    • 3 years ago
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    Yep.

  30. alfers101
    • 3 years ago
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    i think we're going to do a standard equation not quadratic equation?!

  31. alfers101
    • 3 years ago
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    standard form rather

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