## alfers101 Group Title Quadratic Equation: (x-4)(x-6)=2 one year ago one year ago

1. terenzreignz

You're supposed to find x, am I right? :)

2. alfers101

haha i dont know :) i think yes?

3. terenzreignz

Well, perform the FOIL method on (x-4)(x-6). You get...?

4. alfers101

what will you do with 2?

5. terenzreignz

Patience :) FOIL method on the left-hand-side you get x² - 10x + 24 right?

6. alfers101

yes

7. terenzreignz

so... x² - 10x + 24 = 2 Now you can more clearly see what to do with the 2, am I right? ;)

8. GaLm

.....

9. GaLm

you cant find x

10. alfers101

then what is it?

11. GaLm

use FOIL

12. GaLm

know what that is?

13. alfers101

yes. i got x^2-10x+24=2

14. alfers101

then whats next?

15. terenzreignz

Now add -2 to both sides

16. alfers101

what?

17. terenzreignz

Well, transpose 2, from the right side to the left... x² - 10x + 22 = 0

18. alfers101

oohh i get it. then what?

19. terenzreignz

Use the quadratic formula. Everything falls into place.

20. alfers101

21. terenzreignz

Given your equation in the form ax² + bx + c = 0 Your x values are given by $\huge \frac{-b \ \pm \ \sqrt{b^2-4ac}}{2a}$

22. terenzreignz

Plug in and solve.

23. alfers101

what is my a ? my b is 10? my c is 24 ?

24. alfers101

i mean my c is 20?

25. terenzreignz

your b is -10 not just 10 a is 1, as there is no coefficient.

26. terenzreignz

c is 22, not 24. Look again.

27. alfers101

oh okay :) then whats next?

28. alfers101

ill just solve it?

29. terenzreignz

Yep.

30. alfers101

i think we're going to do a standard equation not quadratic equation?!

31. alfers101

standard form rather