anonymous
  • anonymous
You are standing at a red light on SW 8th Street at 97th Avenue. The light turns green, you start speeding up, and the moment you reach 98th Avenue you reach a speed of 43 mph. What is the work done on your 1,277-kg car by the frictional force excerted from the road on the tires.
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Every 10 avenues is .1 miles
amistre64
  • amistre64
im not sure that i understand the question as stated. With the information given, we could possibly determine the acceleration of the car and Force = mass x accel. Im thinking work is equal to Force x distance. But there is not coeffs of friction given or total energy of the system/ loss with which to compare with. So im pretty much stymied ....
anonymous
  • anonymous
That is exactly how I feel it only says that so I don't even know what to do

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amistre64
  • amistre64
since a tire is round, would we have to play with the circle versions? i dont see that being a viable option since we dint know the radius .... I think its just asking us the work done to move the car
amistre64
  • amistre64
What are our definitions of Work?
amistre64
  • amistre64
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amistre64
  • amistre64
43, not 45
amistre64
  • amistre64
\[\frac{1}{2\Delta x}(v_f^2-v_o^2)=a\] you say from 97 to 98 is .1 miles/10; for a distance of .01 miles?
amistre64
  • amistre64
the track at the high school is .25 miles oval so the straight run is about .1 miles. and they have 10 intersection in that length?
anonymous
  • anonymous
Thank you, I atually figured it out earlier but seeing this just assured me! <3
anonymous
  • anonymous
it's actually just the change in kinetic energy, we use the conservation of energy and assume that,\[\frac{ 1 }{ 2 }m(v_f-v_i)^2=Friction\]
amistre64
  • amistre64
cool :)

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