## lizki Group Title Can someone send me a link,where finding torque is explained simply ? one year ago one year ago

1. amistre64 Group Title

Force times distance ..... right?

2. lizki Group Title

yes ,but i find them hard when we also have cos37 and sin37!

3. amistre64 Group Title

thats part of vectors then, and not really torque ... im assuming is there a more specific problem that we can relate these to?

4. lizki Group Title

This example is solved in my book,but i cant understand the procedure! -The force applied to a 0.2m long spanner is 15N.Find the torque produced by this force.(take cos37=0.8 and sin37=0.6)

5. amistre64 Group Title

then tag me in your post so I can have a look see later please

6. lizki Group Title

|dw:1361799280435:dw|

7. amistre64 Group Title

we want to find the part of the force that is perpendicular to the spanner

8. amistre64 Group Title

|dw:1361799368979:dw|

9. amistre64 Group Title

the amount of force applied at a right angle to the spanner is therefore: 15 sin(37) and the distance is already given as : .2m you said?

10. lizki Group Title

yes 2 m

11. amistre64 Group Title

so your question is not about torque ... but rather how to find the required adjustment of the force.

12. amistre64 Group Title

which is just your right triangle material :)

13. lizki Group Title

But the topic in the book is 'TORQUE' but anw,thenkyou :)

14. amistre64 Group Title

youre welcome; and yes, torque is the new material that they are adding to the old material from previous sections :) good luck

15. UnkleRhaukus Group Title
16. Iamgmg90 Group Title

$Torque = \overrightarrow{F} \times \overrightarrow{r} \times Sin \Theta$

17. lizki Group Title

thankyou alot