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amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1Force times distance ..... right?

lizki
 2 years ago
Best ResponseYou've already chosen the best response.0yes ,but i find them hard when we also have cos37 and sin37!

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1thats part of vectors then, and not really torque ... im assuming is there a more specific problem that we can relate these to?

lizki
 2 years ago
Best ResponseYou've already chosen the best response.0This example is solved in my book,but i cant understand the procedure! The force applied to a 0.2m long spanner is 15N.Find the torque produced by this force.(take cos37=0.8 and sin37=0.6)

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1then tag me in your post so I can have a look see later please

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1we want to find the part of the force that is perpendicular to the spanner

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1361799368979:dw

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1the amount of force applied at a right angle to the spanner is therefore: 15 sin(37) and the distance is already given as : .2m you said?

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1so your question is not about torque ... but rather how to find the required adjustment of the force.

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1which is just your right triangle material :)

lizki
 2 years ago
Best ResponseYou've already chosen the best response.0But the topic in the book is 'TORQUE' but anw,thenkyou :)

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1youre welcome; and yes, torque is the new material that they are adding to the old material from previous sections :) good luck

Iamgmg90
 2 years ago
Best ResponseYou've already chosen the best response.0\[Torque = \overrightarrow{F} \times \overrightarrow{r} \times Sin \Theta \]
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