## anonymous 3 years ago Can someone send me a link,where finding torque is explained simply ?

1. amistre64

Force times distance ..... right?

2. anonymous

yes ,but i find them hard when we also have cos37 and sin37!

3. amistre64

thats part of vectors then, and not really torque ... im assuming is there a more specific problem that we can relate these to?

4. anonymous

This example is solved in my book,but i cant understand the procedure! -The force applied to a 0.2m long spanner is 15N.Find the torque produced by this force.(take cos37=0.8 and sin37=0.6)

5. amistre64

then tag me in your post so I can have a look see later please

6. anonymous

|dw:1361799280435:dw|

7. amistre64

we want to find the part of the force that is perpendicular to the spanner

8. amistre64

|dw:1361799368979:dw|

9. amistre64

the amount of force applied at a right angle to the spanner is therefore: 15 sin(37) and the distance is already given as : .2m you said?

10. anonymous

yes 2 m

11. amistre64

so your question is not about torque ... but rather how to find the required adjustment of the force.

12. amistre64

which is just your right triangle material :)

13. anonymous

But the topic in the book is 'TORQUE' but anw,thenkyou :)

14. amistre64

youre welcome; and yes, torque is the new material that they are adding to the old material from previous sections :) good luck

15. UnkleRhaukus
16. anonymous

$Torque = \overrightarrow{F} \times \overrightarrow{r} \times Sin \Theta$

17. anonymous

thankyou alot