anonymous
  • anonymous
Can someone send me a link,where finding torque is explained simply ?
Physics
chestercat
  • chestercat
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amistre64
  • amistre64
Force times distance ..... right?
anonymous
  • anonymous
yes ,but i find them hard when we also have cos37 and sin37!
amistre64
  • amistre64
thats part of vectors then, and not really torque ... im assuming is there a more specific problem that we can relate these to?

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anonymous
  • anonymous
This example is solved in my book,but i cant understand the procedure! -The force applied to a 0.2m long spanner is 15N.Find the torque produced by this force.(take cos37=0.8 and sin37=0.6)
amistre64
  • amistre64
then tag me in your post so I can have a look see later please
anonymous
  • anonymous
|dw:1361799280435:dw|
amistre64
  • amistre64
we want to find the part of the force that is perpendicular to the spanner
amistre64
  • amistre64
|dw:1361799368979:dw|
amistre64
  • amistre64
the amount of force applied at a right angle to the spanner is therefore: 15 sin(37) and the distance is already given as : .2m you said?
anonymous
  • anonymous
yes 2 m
amistre64
  • amistre64
so your question is not about torque ... but rather how to find the required adjustment of the force.
amistre64
  • amistre64
which is just your right triangle material :)
anonymous
  • anonymous
But the topic in the book is 'TORQUE' but anw,thenkyou :)
amistre64
  • amistre64
youre welcome; and yes, torque is the new material that they are adding to the old material from previous sections :) good luck
UnkleRhaukus
  • UnkleRhaukus
https://www.khanacademy.org/science/physics/torque-angular-momentum/torque-tutorial/v/introduction-to-torque
anonymous
  • anonymous
\[Torque = \overrightarrow{F} \times \overrightarrow{r} \times Sin \Theta \]
anonymous
  • anonymous
thankyou alot

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