Here's the question you clicked on:
lizki
Can someone send me a link,where finding torque is explained simply ?
Force times distance ..... right?
yes ,but i find them hard when we also have cos37 and sin37!
thats part of vectors then, and not really torque ... im assuming is there a more specific problem that we can relate these to?
This example is solved in my book,but i cant understand the procedure! -The force applied to a 0.2m long spanner is 15N.Find the torque produced by this force.(take cos37=0.8 and sin37=0.6)
then tag me in your post so I can have a look see later please
we want to find the part of the force that is perpendicular to the spanner
|dw:1361799368979:dw|
the amount of force applied at a right angle to the spanner is therefore: 15 sin(37) and the distance is already given as : .2m you said?
so your question is not about torque ... but rather how to find the required adjustment of the force.
which is just your right triangle material :)
But the topic in the book is 'TORQUE' but anw,thenkyou :)
youre welcome; and yes, torque is the new material that they are adding to the old material from previous sections :) good luck
\[Torque = \overrightarrow{F} \times \overrightarrow{r} \times Sin \Theta \]