## Babyslapmafro Group Title Could someone please verify that I solved the following integral correctly (click to see). one year ago one year ago

1. Babyslapmafro Group Title

$\int\limits_{}^{}\tan(x)\sec ^{3}(x)dx$ $=\int\limits_{}^{}\tan(x)\sec(x)\sec ^{2}(x)dx$ $=\int\limits_{}^{}\tan(x)\sec(x)u ^{2}\frac{ du }{ \sec(x)\tan(x) }$ $=\int\limits_{}^{}u ^{2}du=\frac{ \sec ^{3}(x) }{ 3 }+C$

2. Babyslapmafro Group Title

Idk if what I did was legal, but I got the right answer

3. TuringTest Group Title

Wes you solved it correctly, though you mixed your variables. You should never have u and x in the same expression.

4. TuringTest Group Title

Yes*

5. Babyslapmafro Group Title

I've seen u's and x's in the same expression many times, that's how x values are canceled and u's remain

6. TuringTest Group Title

I would have written$\int\sec^3x\tan xdx=$$\int\sec^2x\sec x\tan xdx$$u=\sec x\implies du=\sec x\tan xdx$and just subed in i'm not saying that what you did is totally wrong, I'm just saying it's a bad habit, and may confuse you later on. I do the trick you are referring to if I have only a constant that appears due to the u-sub, but with other variables it can get confusing. Still, right answer, nice job.