anonymous
  • anonymous
23. Name three faces of the cube above that intersect at point G. (1 point) a. DHGC, CBFG, GFEH b. ABFE, ADHE, ABCD c. DCBA, GEBF, GFEH d. GDAF, CBFG, GFEH 26. Find the surface area of the cylinder to the nearest tenth of a square unit. Use pi. = 3.14. a. 206 cm2 b. 100.5 cm2 c. 623 cm2 d. 412 cm2 mc0262.jpg nar0021.jpg
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
http://assets.openstudy.com/updates/attachments/4f623c14e4b079c5c63146fa-%253C3smart_kidd3%253E-1331837992149-mc0262.jpg
anonymous
  • anonymous
http://assets.openstudy.com/updates/attachments/4f623c14e4b079c5c63146fa-%253C3smart_kidd3%253E-1331837991605-nar0021.jpg
anonymous
  • anonymous
I'll give you one face for the cube, and you should be able to find two more. One is ABCD.

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More answers

anonymous
  • anonymous
As for the surface area of the cylinder.. do you know the formula to find the surface area of a cylinder?
anonymous
  • anonymous
no..
anonymous
  • anonymous
which unit and lesson
anonymous
  • anonymous
unit 2 lesson 16. 7th grade
anonymous
  • anonymous
Here's the formula for the surface area of a cylinder: \[2\pi r ^{2} + 2\pi r h\] Where r = radius h = height \[\pi = p i\]and pi = 3.14
anonymous
  • anonymous
Do you know how to plug your values in?
anonymous
  • anonymous
ohh im in 10th grade lol
anonymous
  • anonymous
No....
anonymous
  • anonymous
i tried but i got a WAY different answer then the answers provided..
anonymous
  • anonymous
What values did you plug into where? (what did you use for the radius and what did you use for the height?)
anonymous
  • anonymous
wait i think i got it is it 412???
anonymous
  • anonymous
Well, here's how it should look before solving:\[(2)(3.14)(4^{2}) + (2)(3.14)(4)(12.4)\]
anonymous
  • anonymous
If you simplify that by squaring the radius, then it's: (2)(3.14)(16) + (2)(3.14)(4)(12.4) How would you go bout solving this?
anonymous
  • anonymous
|dw:1361818233566:dw|
anonymous
  • anonymous
Yes! Very good!
anonymous
  • anonymous
Thx!!

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