## Rugtugba 2 years ago if csc( weird squiggly thing) = 13/5 then what would sec sin cos and tan = ?

1. amistre64

design a rt triangle with sides corresponding to the definition of csc, and then you can determine the missing side to fill in the other trig ratios

2. amistre64

or you can do a pythag method that doesnt rely on geometry

3. Rugtugba

so then 13 is the long side 5 is the short side and when added together its 18?

4. amistre64

almost, its good to remember that sin and csc are flips of each other so if csc = 13/5, then sin = 5/13 sin = over/hyp |dw:1361828131737:dw|

5. amistre64

cos = next.to/hyp = sqrt(...)/13 sec and cos are flips tan = over/next.to = 5/sqrt(...) tan and cot are flips

6. Rugtugba

so then sec and cos are the same answer tan is diffrent right?

7. amistre64

sec and cos use the same numbers; but are flipped versions of each other

8. Rugtugba

ok so sin i 5 / 13 then right?

9. amistre64

yes it might help to figure out the sqrt part, youll need it :)

10. Rugtugba

sqrt is 12

11. amistre64

good, then define the trig functions for me :)

12. Rugtugba

so then tan would be 5/12 and sec would be 5/13 cos would be 13/5 and sin would be 5/13

13. Rugtugba

or did i mix up sec and cos ?

14. amistre64

youve got the right ideas, but need practice: given: csc = 13/5 , then sin = 5/13 we know the missing side is 12 now cos = 12/13 , therefore sec = 13/12 tan = 5/12, therefore cot = 12/5

15. Rugtugba

*face palm * thank you so much

16. amistre64

keep up the practice, youre doing fine :)

17. amistre64

trig is like 90 percent memorization