Here's the question you clicked on:
Rugtugba
if csc( weird squiggly thing) = 13/5 then what would sec sin cos and tan = ?
design a rt triangle with sides corresponding to the definition of csc, and then you can determine the missing side to fill in the other trig ratios
or you can do a pythag method that doesnt rely on geometry
so then 13 is the long side 5 is the short side and when added together its 18?
almost, its good to remember that sin and csc are flips of each other so if csc = 13/5, then sin = 5/13 sin = over/hyp |dw:1361828131737:dw|
cos = next.to/hyp = sqrt(...)/13 sec and cos are flips tan = over/next.to = 5/sqrt(...) tan and cot are flips
so then sec and cos are the same answer tan is diffrent right?
sec and cos use the same numbers; but are flipped versions of each other
ok so sin i 5 / 13 then right?
yes it might help to figure out the sqrt part, youll need it :)
good, then define the trig functions for me :)
so then tan would be 5/12 and sec would be 5/13 cos would be 13/5 and sin would be 5/13
or did i mix up sec and cos ?
youve got the right ideas, but need practice: given: csc = 13/5 , then sin = 5/13 we know the missing side is 12 now cos = 12/13 , therefore sec = 13/12 tan = 5/12, therefore cot = 12/5
*face palm * thank you so much
keep up the practice, youre doing fine :)
trig is like 90 percent memorization