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Rugtugba

  • 2 years ago

if csc( weird squiggly thing) = 13/5 then what would sec sin cos and tan = ?

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  1. amistre64
    • 2 years ago
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    design a rt triangle with sides corresponding to the definition of csc, and then you can determine the missing side to fill in the other trig ratios

  2. amistre64
    • 2 years ago
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    or you can do a pythag method that doesnt rely on geometry

  3. Rugtugba
    • 2 years ago
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    so then 13 is the long side 5 is the short side and when added together its 18?

  4. amistre64
    • 2 years ago
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    almost, its good to remember that sin and csc are flips of each other so if csc = 13/5, then sin = 5/13 sin = over/hyp |dw:1361828131737:dw|

  5. amistre64
    • 2 years ago
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    cos = next.to/hyp = sqrt(...)/13 sec and cos are flips tan = over/next.to = 5/sqrt(...) tan and cot are flips

  6. Rugtugba
    • 2 years ago
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    so then sec and cos are the same answer tan is diffrent right?

  7. amistre64
    • 2 years ago
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    sec and cos use the same numbers; but are flipped versions of each other

  8. Rugtugba
    • 2 years ago
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    ok so sin i 5 / 13 then right?

  9. amistre64
    • 2 years ago
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    yes it might help to figure out the sqrt part, youll need it :)

  10. Rugtugba
    • 2 years ago
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    sqrt is 12

  11. amistre64
    • 2 years ago
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    good, then define the trig functions for me :)

  12. Rugtugba
    • 2 years ago
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    so then tan would be 5/12 and sec would be 5/13 cos would be 13/5 and sin would be 5/13

  13. Rugtugba
    • 2 years ago
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    or did i mix up sec and cos ?

  14. amistre64
    • 2 years ago
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    youve got the right ideas, but need practice: given: csc = 13/5 , then sin = 5/13 we know the missing side is 12 now cos = 12/13 , therefore sec = 13/12 tan = 5/12, therefore cot = 12/5

  15. Rugtugba
    • 2 years ago
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    *face palm * thank you so much

  16. amistre64
    • 2 years ago
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    keep up the practice, youre doing fine :)

  17. amistre64
    • 2 years ago
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    trig is like 90 percent memorization

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