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I need help with question b at . Thanks. :)

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Please help me?
hmm, I think its \[3\over15\] but I'm not exactly possitive.

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Other answers:

Hmm. Could you explain,please?
uhm. let me read that again.
how did u get /31?
I added together all of the numbers and then took the number of reds and put it over that and simply reduced it. But I'm not sure I did it right because of the way that the question was asked. Oh and @zupster 6+8+5+9+2=30 not 25.
You're welcome(: idk If I helped or not.
I think you did:)
Thank you.
No problem :D ♥
wait, mitt
i have a question.
I still need to pee ._. lol
do you know what it means by 'without replacing the other candy'?
then, perhaps it's 10 over 30, which would mean that it would be 1/3
The probability of selecting red is 9 / 30. The probability of selecting red for second time is 8 / 29.
So what is the answer?
8 / 29?
Sorry, you're on your own.
How is the probability the second time 8/29? you took away two candies didnt you?
That doesnt seem right..
No, it is asking what is the probability of selecting 2 red ones.
On part A i got 1/90
maybe that has something to do w/it?
I can doublr check this with a teacher if you want.
Thats okay. :)
I'm doing it anyway :P I dont want you to have the wrong answer c:
A) \[\frac{ 2 }{ 30 }=\frac{ 1 }{ 15 } purple\] \[\frac{ 5 }{30}=\frac{ 1 }{ 6 } orange\] \[\frac{ 1 }{ 15 }•\frac{ 1 }{ 6 }=\frac{ 1 }{ 90 }\] Good job(: B) \[\frac{ 1 }{ 15 }•\frac{ 9 }{ 29 }=\frac{ 3 }{ 145 }\] Do you understand? :o
Thanks, do u simplify?
It is simplified(:
oks. i have some more probs tho. tnx for helping me. and tell ur teacher i said thanks:)
let me post the new q. can i tag u?
tnx u. :)
am posting.

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