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anonymous
 3 years ago
can someone please help me find these values?
anonymous
 3 years ago
can someone please help me find these values?

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NoelGreco
 3 years ago
Best ResponseYou've already chosen the best response.0For someone to comment, he's have to know more about the lab.

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1the moles you can simply find by dividing the masses by their molar mass... for the volume of H2 formed, you need to write the equation of the reaction in your exp and work with that.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@aaronq so for magnesium it would be 24.31/0.035?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh ok and for h2? @aaronq

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1you have to find the volume first

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is the volume of hydrogen gas produced the same as teh volume of liquid displaced? @aaronq

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1unless you made other gases in your experiment

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so the volume divided by the mass of h2 will give me the moles of h2?

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1well for ideal gases you can just use the fact that 1 mole = 22.414 L at STP

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1otherwise you have to know the density of the gas

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0therefore, how would the equation look?

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1so for ideal gases, moles = volume of gas/(22.414 L/mol)

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1make sure you have the same units

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@aaronq for the moles of magnesium igot 0.001 for all the trials, but my friend wrote it in dimensional analysis . whats betteR?

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1it's the same thing, since it's a gas, the volume is proportional to the amount of moles

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok and how would i find the ratio of volume displaced in mL to moles h2 gas produced? @aaronq

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1a ratio is just a division volume of gas/moles of gas

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so volume of h2/moles of h2?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@aaronq i get a huge number

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1yep, thats what the want

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1they actually want the volume displaced/molesof H2 which is the same thing

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1to what they're asking you, yes

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but its such a big number? @aaronq

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1yep thats not that big of a number, remember it's in mL ..

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1lol that's not a lot, it really should be around 22.414 L

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1well unless they want you to calculate using Mg (s) + HCl > H2 + MgCl (aq)

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1this would be the theoretical way you balance the equation and use diminutional analysis, but really your answer is gonna be like off by very little, also, because of rounding

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1did they give you the concentration of the acid?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0all we had to do was place a piece of magnesium inside a buret that contained hcl and this was then converted and all the hcl migrated down to the bottom of the buret

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0basically the magnesium was reacting with the hcl

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and after that we had to find the values in that table

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1hm well they really wouldn't need to tell you, do you know what a limiting reagent is?

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1yep, it's the same thing. you could use the number of moles of that and translate it to moles of H2 produced 2Mg (s) + 2HCl > H2 + 2MgCl (aq) 0.001439 moles of Mg/2 = x moles of H2/1 moles of H2 = 0.0028794734677088 thats the theoretical yield

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well that makes more sense because thats what we are currently learning in class haha

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1oh wait sorry i multiplied, it should be moles of H2 = 0.0007198683669272

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1haha oh true, well maybe let me know next time? haha

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so in other words, to find lets say trial #1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0where the volume of hydrgen gas produced was 37.00mL and the moles of h2 gas produced were 0.002 mol

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1you would convert the mass of Mg to moles then using the balanced equation, build a relationship between H2 and Mg using their respective coefficients.. this just means: moles of Mg/coefficient=moles of H2/coefficient

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0moles of mg that reacted?

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1yeah because thats your limiting reactant..

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1wait no i balanced it wrong because it's Mg + 2HCl > MgCl2 + H2

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1so it's coefficient is 1 for both

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1sorry, i'm like lost today idk why

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1Mg (s) + 2HCl > H2 + MgCl2 0.001439 moles of Mg/1 = x moles of H2/1 moles of H2 = 0.001439 thats the theoretical yield which is close to what you would get if you just divided the volume of gas produced by 22.414 L

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but what value would i put?

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1i would go with the theoretical since thats what you're doing in class

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1yeah, even round up to 0.0015

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok wait where did the 0.001439 come from>?

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1its the number of moles of magnesium

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ooooh yes thats my 0.001

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1haha yep, i mean round to whatever you think it's best, or whatever they're teaching you at school

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but for the ratio isnt moles of h2 divided by moles of magnesium? so 0.002h2/0.001mg

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ratio of volume displaced to moles h2 gas prodced

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1well the amount of moles of H2 produced is equal to the moles of Mg that reacted according to the stoichiometric ratios of the equation... so to answer your question it would be 37 mL/0.001 moles.. which is what you had before, if i remember correctly

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.037 being the volume of hydrogen gas produced and 0.001 moles of magnesium reacted?

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1well, technically yes, but the question is asking for the volume displaced divided by the moles of H2 produced..which are the same values

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh so volume of liquid displaced divided by the moles of h2

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1that they're asking you for in the question yes. They're basically seeing how close that value is to the ideal gas constant volume of 1 mole =22.414 L, since 37mL/0.0014 mol = 26428.5714285714285714 mL/mol 26.428 L/mol so it's close if you use more than 0.001, which i think you should do lol

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh my i get the big number again hahaha

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1your friend in the other thread used 0.00144 moles

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.00.0014 is in the correct significant figures? i keep using 0.001

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1hm idk though if you don't use that your error is pretty large

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but look when i divide 0.035/ 24.31

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and the right sig figures are four so you round it to 0.001?

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1well zeros on the left side

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so now its 3 sig figures?

aaronq
 3 years ago
Best ResponseYou've already chosen the best response.1i would use 2 sig digits b/c 0.035 .. and have 0.0014

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so only 14 are significant

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what about 0.016/24.31
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